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Assignment No. 01
Semester: Fall  2016
Digital Logic Design – CS302

Topics Covered: Number systems to

Boolean Algebra & Logic Simplification

 

Total Marks: 20

 

Due Date: 14 Nov, 2016

 

Objectives:

To understand different Number Systems with its conversion from one to another and Boolean Algebra with its implementation with Logic Gates.

Instructions:

Please read the following instructions carefully before submitting assignment:

It should be clear that your assignment will not get any credit if:

 

  • The assignment is submitted after due date.
  • The assignment is submitted via email.
  • The assignment is copied from Internet or from any other student.
  • The submitted assignment does not open or file is corrupt.
  • It is in some format other than .doc/docx.

 

Note: All types of plagiarism are strictly prohibited.

For any query about the assignment, contact at CS302@vu.edu.pk

 

 

 

Important!

You have to provide all the steps of processing in all questions otherwise, marks will be deducted.

Question No. 01                                                                                                                          5 Marks

In the binary number system, we represent numeric values using two different symbols which is typically 0 and 1. Suppose we have a tertiary number system, which consists of three different symbols i.e. 0, 1 and 2. You have to perform the following operation defined in a given expression where we have to subtract a tertiary number from a decimal number and have to express the output in a binary number system.

(576)10 – (110002)3 = (_?_)2

 

Question No. 02 (a)                                                                                                                     7 Marks

Suppose we have a digital circuit expressed through the following truth table. You have to write simplified Boolean expression using Boolean Algebra.

Note: You have to write the Boolean Algebra Rule name for each simplification step.

 

A

B

C

D

Output=Y

0

0

0

0

1

0

0

0

1

1

0

0

1

0

0

0

0

1

1

0

0

1

0

0

0

0

1

0

1

1

0

1

1

0

0

0

1

1

1

1

1

0

0

0

1

1

0

0

1

1

1

0

1

0

0

1

0

1

1

0

1

1

0

0

0

1

1

0

1

0

1

1

1

0

0

1

1

1

1

0

 

Question No. 02 (b)                                                                                                                    8 Marks

Draw the circuit diagram for the simplified Boolean expression obtained from Question No. 02 (a).

 

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Dear Students Don’t wait for solution post your problems here and discuss ... after discussion a perfect solution will come in a result. So, Start it now, replies here give your comments according to your knowledge and understandings....

mn ne 2nd question kr lia hai..pr confrm ni hai

please share 2nd question answer, lets check how u resolved.

can u share ,Is ki smajh nhi a rhi.

first or last expression send post kr dn.. ap chk kr dena

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Attachments:

i thnk yeh circuit lgt hai..blky waqai ghlt hai.. mtlb k jo end p simplified expression aye g us ka circuit bnana hai na k first wali expression ka 

sir ye to multiplexer h with abel code past assignment

B'C'+A'BD ka circuit bnana hai na? 

yeh answer correct hy

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