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Assignment # 1       MTH202 (Fall 2016)

 

                                                                                              Maximum Marks: 10                                                                                       

                                                                                                     Due Date: 14 -11-2016

 

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Question No. 1:

 

Using the truth table show that                      

 

 

 

Question No. 2:

 

Using the laws of logic show that      

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Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

Dear Students Don’t wait for solution post your problems here and discuss ... after discussion a perfect solution will come in a result. So, Start it now, replies here give your comments according to your knowledge and understandings....

Discuss on Question No.2.

kon kon se laws apply hun gay is pe

aoa brothers i send u some law of Discreat Mathmatics
check these any 1,,,

1. Commutative laws: p∧q ≡ q∧p p∨q ≡ q∨p
2. Associative laws: (p∧q)∧r ≡ p∧(q∧r) (p∨q)∨r ≡ p∨(q∨r)
3. Distributive laws: p∧(q∨r) ≡ (p∧q)∨(p∧r) p∨(q∧r) ≡ (p∨q)∧(p∨r)
4. Identity laws: p∧t ≡ p p∨c ≡ p
5. Negation laws: p∨∼p ≡ t p∧∼p ≡ c
6. Double negative law: ∼(∼p) ≡ p
7. Idempotent laws: p∧p ≡ p p∨p ≡ p
8. Universal bound laws: p∨t≡t p∧c≡c
9. De Morgan’s laws: ∼(p∧q) ≡ ∼p∨∼q ∼(p∨q) ≡ ∼p∧∼q
10. Absorption laws: p∨(p∧q) ≡ p p∧(p∨q) ≡ p
11. Negations of t and c: ∼t ≡ c ∼c ≡ t
The first circuit is equivalent to this: (P∧Q) ∨ (P∧~Q) ∨ (~P∧~Q), which I managed to simplify to this: P ∨ (~P∧~Q).

The other circuit is simply this: P ∨ ~Q

+ AiM thanks for sharing 

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Follow the link for Question 2

IDEA Solution

Student Id:                 

MTH 202       Question No 1

p

q

pÚq

p→r

q→r

(pÚq)→r

(p→q) Ù(q→r)

T

T

T

T

T

T

T

T

T

T

F

T

F

F

F

F

T

F

T

T

T

T

T

T

T

F

F

T

F

T

F

F

F

T

T

T

T

T

T

T

F

T

F

T

T

F

F

F

F

F

T

F

T

T

T

T

F

F

F

F

T

T

T

T

As you show that Value of (pÚq)→r is same to (p→q) Ù(q→r) so we written.

(pÚq)→r≡(p→q) Ù(q→r)

Question No 2

p

q

r

~p

~q

p∧r

q∧r

∼q∧r

∼p∧(∼q∧r)

(∼p∧(∼q∧r)⋁(q∧r)

((∼p∧(∼q∧r))∨(q∧r)⋁(p∧r)

((∼p∧(∼q∧r))∨(q∧r)⋁(p∧r)↔r

T

T

T

F

F

T

T

F

T

T

T

T

T

T

F

F

F

F

F

T

F

F

F

T

T

F

T

F

T

T

F

T

F

T

T

T

T

F

F

F

T

F

T

F

T

T

T

F

F

T

T

T

F

F

T

F

F

F

F

F

F

T

F

T

F

T

F

T

T

T

T

T

F

F

T

T

T

F

F

T

T

T

T

T

F

F

F

T

T

T

T

F

F

T

T

T

So we Show that:                    ((∼p∧(∼q∧r))∨(q∧r)⋁(p∧r)↔r

the 2nd  is wrong

ap ny Q2 kia hai

IDEA Solution file Attached

Attachments:

Q2 ANS IS WRONG

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