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Cyberian.pk  ap ye keh rhe hu k tariq bhai ka answer thek hai

Right answer by tariq bhai because on v3 we have an edge loop hence, it is not isolated.

Find all edges which are incident on v5, all vertices that are adjacent to v5, all loops, all parallel edges and all isolated vertices of the graph given below.

Solution:
(i) v5 is incident with edges e6, e7 and e8.
(ii) vertices adjacent to v5 are v4 and v6
(iii) loops are e1, e4 and e5
(iv) edges e2 and e3, e8 and e7 are parallel
(v) The only isolated vertex is v3 in this Graph.

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