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eh lo Nomi Gill
3 marks questions
1) find contribution rate
2) find selling price
2marks questions
1) find contribution margin
2) suppose 0.4 of a number is equal to 0.06 of another number find ratio between them???
5 marks questions
1) find no of unit sold above breakeven point
1 question bhool gai
plzzzzzz agar ratio valy ka answer n process kisi ko pata ho to bata dain
maine yeh question koi nai kiyaa
excel k formulaaazzzzzz ka ratta laga laga ker ...kuch b nai aayaa
mcqus Markup....down ...and matrices main sy thy
best of luk NG
HERE IS MY PAPER I HOPE I ATTEMPT RIGHT ANSWERS
An article costing Rs.500 is sold at 10% loss. Find its selling price. 2 marks
Cost = 500
Loss rate = 10%
Selling price = cost (1 loss rate)
Selling price = 500 (1.10)
Selling price = 500 (.90)
Selling price = 450
What is the formula for contribution rate? 2 marks
Contribution rate = (contribution margin / net sales ) *100
A shoe store uses a 40% markup on cost. Find the cost of a pair of shoes that sells for $63? 3 marks
Selling price = 63
Muc = 40%
Selling price = cost price * (1+muc)
63 = cost price (1+.40)
63 = cost price1.40
Cost price = 63/1.40
Cost price = 45
Find NPV of given data. 3 MARKS
20 
RATE 


260000 
INTIAL INVESTMENT 


40000 
CASH FLOW IN FIRST YEAR 

45000 
CASH FLOW IN SECIND YEAR 

50000 
CASH FLOW IN THIRD YEAR 
Evaluate the sum of the years digits depreciation of an asset having the cost of Rs.10,000 for a period of 5 years such that salvage value after 7 years is Rs.5000. 5 marks
Cost price = Selling price – (Selling price × %Markup on sale)
= Selling price ( 1 – %Markup on sale)
Evaluate the sum of the years digits depreciation of an asset having the cost of Rs.10, 000 for a period of 5 years such that salvage value after 7 years is Rs.5000.
Solution
Cost Price Rs.10, 000
Salvage value after 7 years Rs.5, 000
Depreciable Value =Cost Price – Salvage value
=10,0005,000
=5,000
Sum of Years digit depreciation. =7+6+5+4+3+2+1
=28
1st year depreciation =7/28*5000 =Rs.1, 250
2^{nd} year depreciation =6/28*5000 =Rs.1, 071
3rd year depreciation =5/28*5000 =Rs.893
4^{th} year depreciation =4/28*5000 =Rs.714
5^{th} year depreciation =3/28*5000 =Rs.536
Nomi Gill thanks for sharing ur paper..
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wafa ye hy question no.2 solved...
Let one nmber be 'x' and another be 'y'.
Now, given tht,
0.4x = 0.06y
x/y = 0.06/0.4
or x:y = 0.06:0.4 = 0.15
Plz Pray for me...
cncpt clear rakhein....n main frmulas etc yaad.....confuse ni hona
bst of luck.....
Today’s Current Midterm Paper
Total Questions = 26
Total MCQ = 20
2 Questions of 2 Marks
2 Questions of 3 Marks
2 Questions of 5 Marks
1 Question from Sum of the year depreciation (SYD).
2 Questions were from Ratios.
1 Question from Mark Down.
1 Question from Mark UP.
1 was the definition of Contribution margin (CM).
Total Questions: 26 Total Marks: 40
Total MCQs of 1 Mark: 20
Short Subjective Question of 2 Marks: 2
Subjective Question of 3 Marks: 2
Subjective Questions of 5 Marks: 2
Q1 After consuming 88% of income, Ali left with Rs.240, what is income? 3 marks
Q2 6 stools and 3 chairs, bought at $58, 3 stools and 2 chairs bought at $35...What is price of stools and chairs?
Solution
X=Stools Y=Chairs
Put in equation
6x+3y=58...............A
3x+2y=35................B
Subratct A from B and get values and put them in any equation, u ll get ans.
Q3 Calculate BEP in units, if %capacity is 320, CM is 45, sale price is 85 per unit?
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