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           Lectures # 34-39 

           Due date: 04-08-2017                                                               

  

 

Problem                                                                                            Marks 10

 

 

An iron rod at temperature  is allowed to cool down in air at room temperature of 300K. Assuming heat is lost due to radiation, the differential equation for temperature of the rod is given by

 

Where is in K and   in seconds.

Find the temperature at seconds using fourth- order Runge-Kutta method. Assume step size of seconds

 

 

 

Note:

i)                    Only doc or docx files with editable and accessible math type codes will be marked. Files like JPG, PDF, PNG etc. or even solution image in doc or docx file will not be entertained.

ii)                   50% marks will be deducted in case of submission through mail after the due date.

iii)                 Solution file will be uploaded on Monday, August 7, 2017 at 10:00am, after that no assignment will be accepted even through mail.

 

 

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I have Example almost identical to this question. Click Here Identical Question

guys kya k2, k3 ,k4 ki values same aa rahe hain at theta =1200 pay??lets discuss if u have solve it??

what is your answers of step 1 and step 2 k1 to k4

-0.0182727 is it right??

Its a lengthy question and we should compare answers at each step.
Yes this is answer at once of step.

what of the following is the correct answer ? 

please help me out :(

mine is 1198.5384 and 1197.0820
share your solution with me and i with you so we can find out the difference.

What are your answers of k1, k2, k3, k4 for thetha 1?

mine k1=0.0183062 k2=1.058727

is it correct answer?

Kon kon se lecture se aye ha ye assignment?

Lecture 38 se

any one plz seend correct and complete slouation

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