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# Assignment For STA301 Statistics and Probability,Semester Fall 2015 (Due date:Dec 07, 2015)

Assignment no.1 (Lessons 1 – 15)

Question 1:                                                                                                                Marks: 3+2=5

a)      The mean age of a group of 100 persons was found to be 32.02. Later it was discovered that age 57 was misread as 27. Find the corrected mean?

b)      The sum of deviations from an arbitrary value A = 15 for 10 values is 25, find the A.M.

Question 2:                                                                                                               Marks: 3+3=6

a)      The mean of 200 items is 48 and their S.D is 3. Find the values of  and

b)      A vehicle going up from Islamabad to Murree consumes petrol at the rate of One liter per 8 km, while going down from Murree to Islamabad one liter per 12 km. Find the average rate of consumption between the two cities.

Question 3:                                                                                                                         Marks: 4

The S.D of the symmetrical distribution is 5. What must be the value of, and also explain that the distribution will be?

(i)                 Meso-kurtic

(ii)               Platy-Kurtic

(iii)             Leptokurtic

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STA301 assignment solution 2015

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all the answers are right in this solution?

Ye correct solution hyyyyy..????

plz mujhe cs201 k group main add kary

add me in group of mth202....or eng201

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Ap khud himmat kr k group q ni join kr letin dosron ki asry pe bethin hn

Q=1

Mean=∑x/n ........ total age = 32.02*100 = 3202

misread as 27. so subtract 27 from 3202.

3202-27=3175

3175+57=3232

now new corrected mean = 3232/100 = 32.32 answer

A vehicle going up from Islamabad to Murree consumes petrol at the rate of One liter per 8 km, while going down from Murree to Islamabad one liter per 12 km. Find the average rate of consumption between the two cities. is ka ans kia hoga

10. just find simple mean

kse explain it plz

$\begin{gathered} \bar X = \frac{{\sum X }}{n} \hfill \\ = \frac{{20}}{2} = 10 \hfill \\ \end{gathered}$

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