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Assignment No 3 Data communication (CS601) Solution and Discussion Spring 2014 Due Date: July 14, 2014

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Assignment

Question 1: (5 Marks)
When a signal travels from source to destination, it may b affected by different external factors that cause the loss of energy, due to which the signal may differs from its actual shape. In the given table you are required to identify the type of noise with respect to noise source.

Noise Source                                                             Noise Type

Telephone Wire
Water Pump
Earthquake
Extra Signal generated by Motion of Electron
Grinder

Question 2: (5 Marks)
Suppose a signal is generated from a source with initial power of 1000W but due to attenuation it is received at destination (80 Km away from source) with power of 100W. Find the total power loss in decibels by writing formula with all calculation steps.

Question 3: (5 Marks)
Suppose you need to have simultaneous transmission of signals through a single medium, then which technique will be used to fulfill this requirement? Also describe, how does that technique work at sender and receiver end?

NOTE: Do not put any query on MDB about this assignment, if you have any query then email at cs601@vu.edu.pk.

Deadline: Your assignment must be uploaded/submitted on or before 14th July 2014.

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Replies to This Discussion

handout and book me asa koi formula nhi jis sy ham power lose calculate karin

so my personal opinion is we just calculate attenuation (energy lose)

nothing else

r u agree wd me?

yes agee wd u  ayesha

Decibels
Phys 3330
In electronics one
often want
s
to
represent the ratio of two signals on a logarithmic scale. For this we
use the decibel,
dB
. If we have two powers P1and P2
dB = 10 log10(P2/P1)
or equivalently-when comparing two signals
with the same kind of waveform-dB = 20 log10(V2/V1
Note dB is arelativeunit of measurement, i.e. “
This amplifier has a gain of 10 dB.”dBcan be positive or negative. For example, +10 dB corresponds to P2
greater than P1 by a factor of 10, and -3dB  corresponds to P2 less than P1 by approximately a factor of 2.

formula hai na

10 log 10 (p1/p2)

= 10 log 100/1000

= 10 log 0.1

ab answer ko log karna hai

like = 10  log( 0.1 )

    =10 (-1)

     = -10 db

yah but its p2/p1 not p1/p2

Question 2: (5 Marks)

Suppose a signal is generated from a source with initial power of 1000W but due to attenuation it is received at destination (80 Km away from source) with power of 100W. Find the total power loss in decibels by writing formula with all calculation steps.

dB= 10 log10(P2/P1)

dB= 10 log10(100/1000)

dB= 10 log10(0.1)

here log10 means 10 in base of log and calculated by taking simple log of 0.1

dB= 10 (-1)

dB= -10 dB

yup sory 10 log (p2 /P1) sory for mistake likny main galti hoo gaye but answer is true

yr ab demagh me bs yahi arha ha q na DB ko watt me convert kr diya jay...............

 

unhn ne db me manga hy answer na k watt me ayesha 

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