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# CS101 Assignment 01 Spring 2021 Solution / Discussion Due Date: 24-05-2021

CS101 Assignment 01 Spring 2021 Solution / Discussion Due Date: 24-05-2021

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# CS101 Assignment 01 Spring 2021 Solution

CS101_Assignment-01-Solution-Spring_2021-Complete-Solution.docx

#cs101 #cs101assignment #cs101assignmentsolution
CS101 Assignment 1 Solution Spring 2021 || Introduction to Computing || Complete Solution _ Part - 1

# CS101 Assignment 1 Solution Spring 2021 || Introduction to Computing || Complete Solution

#cs101assignment1solution2021 #cs101assignemnt1solutionspring2021
CS101 Assignment 1 Solution Spring 2021 | CS101 Assignment 1 Solution 2021

Great video, completely understood these explanations, God bless you sir.

This is not correct. We need to execute the programs E2, E4, E6 and once the execution have been done, the answers have to be determined.

CS-101 Assignment Solution required

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cs101assignment1solution2021 #cs101assignment1solution2021pdf #cs101assignment12021
cs101 assignment 1 solution 2021 | cs101 assignment 1 2021 | cs101 assignment 1 solution 2021 pdf

Course Code: CS101

Solution

• Determine the contents of register 1 when the machine halts.

ANS = 15

• Write down the bit pattern (in hexadecimal) at memory address F3 when the Halt instruction is executed.

ANS=0705

• How many times the machine instruction at address EE is executed before the machine halts.

ANS = 6

• Determine the contents of register 0 after the instruction at address EC is executed.

ANS=00

• Determine the contents of register 2 when the instruction at address F0 is

ANS=07

Question No.2

• Perform binary addition on given numbers:

20 161 and 7 14.

• Convert the following binary number into ASCII code and then into its equivalent decimal representation.

01001001010000010100110101011100

Part (a)

 24 23 22 21 20 Radix 2-1 2-2 2-3 2-4 16 8 4 2 1 ½ ¼ 1/8 1/18 1 0 1 0 1 1 0 1 0

Ans== 10101.1010

 22 21 20 Radix 2-1 2-2 4 2 1 ½ ¼ 1 0 1 1 0

Ans== 101.10

10101.1010

101.10

100101.0010

Part (b)

 27 26 25 24 23 22 21 20 Answer 128 64 32 16 8 4 2 1 0 1 0 0 1 0 0 1 73 0 1 0 0 0 0 0 1 65 0 1 0 0 1 1 0 1 77 0 1 0 1 1 1 0 0 92

73 = I

65 = A

77 =M

92 = /

IAM/= 01001001010000010100110101011100  ANS

# CS101 Assignment 01 Spring 2021 Solution

CS101_Assignment-01-Solution-Spring_2021-Complete-Solution.docx

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