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CS101

ASSIGNMENT NO 1

Q no 1 solution:

Convert the decimal no into binary and then again into binary:

i)4789

Conversion into binary:

Deviser

Dividend

Reminder

2

4789

1

2

2394

0

2

1197

1

2

598

0

2

299

1

2

149

1

2

74

0

2

37

1

2

18

0

2

9

1

2

4

0

2

2

0

2

0

1

 

4789=(1001010110101)2

Binary to decimal no:

(1001010110101)2=1.212+0.211+0.210+1.29+0.28+1.27+0.26+1.25+1.24+0.23+1.22+0.21+1.20

 (1001010110101)2=4096+0+0+512+128+0+32+16+0+4+0+1

(1001010110101)2=4789

ii)8735

Deviser

Dividend

Reminder

2

8735

1

2

4367

1

2

2183

1

2

1091

1

2

545

1

2

272

0

2

136

0

2

68

0

2

34

0

2

17

1

2

8

0

2

4

0

2

2

0

2

0

1

 

_8735=(10001000011111)2

Binary to decimal:

(10001000011111)2=1.214+0.213+0.212+0.211+1.210+0.29+0.28+0.27+0.26+1.25+1.24+1.23+1.22+1.21+1.20

(10001000011111)2=_(8192+0+0+0+512+0+0+0+0+16+8+4+2+1)

(10001000011111)2=_8735

Q NO2 SOLUTION:

Solve Boolean expression:

[(A⊕D).(A+B)].[( B ̅+C ̅) ⊕(B+C+D)]

 

 

 

A

 

 

 

B

 

 

 

C

 

 

 

D

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

0

0

0

0

0

0

1

0

1

0

0

0

0

0

1

1

0

1

1

0

0

0

0

0

1

0

0

0

1

1

0

0

0

0

0

1

1

1

0

1

1

0

0

0

0

1

0

0

0

1

1

1

0

0

0

0

1

0

1

1

1

1

1

0

1

0

0

1

1

0

0

1

0

1

1

0

0

0

1

1

1

1

1

0

1

1

1

1

1

0

0

0

1

1

1

0

1

1

1

1

0

0

1

0

1

1

1

0

0

0

1

0

1

0

0

1

1

1

0

0

0

1

0

1

1

0

1

1

1

0

0

0

1

1

0

0

1

1

1

0

1

1

1

1

1

0

1

0

1

1

1

0

0

0

1

1

1

0

1

1

0

1

1

1

1

1

1

1

1

0

1

0

1

1

0

0

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