We are here with you hands in hands to facilitate your learning & don't appreciate the idea of copying or replicating solutions. Read More>>

Looking For Something at vustudents.ning.com? Click Here to Search

www.bit.ly/vucodes

+ Link For Assignments, GDBs & Online Quizzes Solution

www.bit.ly/papersvu

+ Link For Past Papers, Solved MCQs, Short Notes & More


Dear Students! Share your Assignments / GDBs / Quizzes files as you receive in your LMS, So it can be discussed/solved timely. Add Discussion

How to Add New Discussion in Study Group ? Step By Step Guide Click Here.

CS401 Assignment No 01 Spring 2019 Solution & Discussion Due Date: 16-05-2019

Q1. Calculate the Effective Address and Physical Address for the following set of values. (10)
Segment: 0xFFFF
Offset =0x0800
Base: 0x0111
Index=0x0001

Q2. Calculate the Segment Address for the given set of Physical and Effective addresses. (10)
Physical address = 0x119B, Effective address = 0x10AB
Physical address = 0xFF9B, Effective address = 0x10FF

Spring%202019_CS401_1.docx

+ How to Follow the New Added Discussions at Your Mail Address?

+ How to Join Subject Study Groups & Get Helping Material?

+ How to become Top Reputation, Angels, Intellectual, Featured Members & Moderators?

+ VU Students Reserves The Right to Delete Your Profile, If?


See Your Saved Posts Timeline

Views: 3184

.

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

+ Click Here to Search (Looking For something at vustudents.ning.com?)

+ Click Here To Join (Our facebook study Group)

Replies to This Discussion

Touseef tahir  thanks for sharing :-) 

 

Share below link with friends for solution & Discussion.

http://bit.ly/vucodes

 

 

+ ! ❤ Sarah ❤  thanks for sharing 

Cs401 1st Assignment Solution 100% Correct

Attachments:
CS401 1st assignment solution.
Q1. Calculate the Effective Address and Physical Address for the following set of values. (10)
Segment: 0xFFFF
Offset =0x0800
Base: 0x0111
Index=0x0001
Solution:
Formula:
Effective Address= Base+off set + index
Physical Address = Segment + Effective Address
First we calculate Effective Address
Effective Address = Base + off set + index
Offset = 0x0800
Base: 0x0111
Index = 0x0001
Effective Address = 0x0111 + 0x0800 + 0x0001
0x0912 Answer
Physical Address = Segment + Effective Address
0xFFFF+0x0912
0x10911 Answer
Q2. Calculate the Segment Address for the given set of Physical and Effective addresses. (10)
a. Physical address = 0x119B, Effective address = 0x10AB
b. Physical address = 0xFF9B, Effective address = 0x10FF
Solution:
Formula:
a) Segment Address = Physical Address – Effective Address
Address = 0x119B -0x10AB = 0x0F0 Answer
b) Segment Address = Physical Address – Effective Address
=0xFF9B – 0x10FF = 0x10911 Answer

CS401 Assignment 1 Solution

Attachments:

CS401 Assignment 1 Solution Spring 2019

Attachments:

sir ya to wrong ha 

RSS

Today Top Members 

© 2019   Created by + M.Tariq Malik.   Powered by

Promote Us  |  Report an Issue  |  Privacy Policy  |  Terms of Service

.