CS402 Assignment No 03 Spring 2019 Solution & Discussion
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Question: Marks=5+5=10Question: Marks=5+5=10As we know that if two languages (L1 & L2) are Regular Languages then L1 ∩L2 is also regular. You have given two regular languages L1 & L2, defined over the alphabet ∑= {a,b}L1= language of words having triple a’s.L2= language of words containing ab. According to these two languages you need to provide a step by step solution for L1 ∩L2 using De-Morgan’s Law.
Solution:
L1= language of words having triple a’s.
The regular expression L1 is as below
R.E = (a+b)* (aaa) (a+b)*
L2= language of words containing ab.
The regular expression L2 is as below
RE = (a+b)* (ab) (a+b)*
Using De-Morgan’s law for sets
(L1C U L2C)C = (L1C)C ∩ (L2C)C = L1 ∩ L2
Please check RE of L1 and L2 is correct.
Where is GTG and its RE?
olution:
L1= language of words having triple a’s.
The regular expression L1 is as below
R.E = (a+b)* (aaa) (a+b)*
L2= language of words containing ab.
The regular expression L2 is as below
RE = (a+b)* (ab) (a+b)*
Using De-Morgan’s law for sets
(L1C U L2C)C = (L1C)C ∩ (L2C)C = L1 ∩ L2
Please check RE of L1 and L2 is correct.
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CS402 Assignment No 03 Solution Spring 2019
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