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CS402 Assignment No 03 Spring 2019 Solution & Discussion

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Question:                                                                             Marks=5+5=10Question:                                                                             Marks=5+5=10As we know that if two languages (L1 & L2) are Regular Languages then L1 ∩L2 is also regular. You have given two regular languages L1 & L2, defined over the alphabet ∑= {a,b}L1= language of words having triple a’s.L2= language of words containing ab. According to these two languages you need to provide a step by step solution for L1 ∩L2 using De-Morgan’s Law. 

Solution:

 

L1= language of words having triple a’s.

 

The regular expression L1 is as below

R.E = (a+b)* (aaa) (a+b)*

 

L2= language of words containing ab.

The regular expression L2 is as below

RE = (a+b)* (ab) (a+b)*

 

Using De-Morgan’s law for sets

(L1C U L2C)C = (L1C)C ∩ (L2C)C = L1 ∩ L2

Please check RE of L1 and L2 is correct.

Where is GTG and its RE?

olution:



L1= language of words having triple a’s.



The regular expression L1 is as below

R.E = (a+b)* (aaa) (a+b)*



L2= language of words containing ab.

The regular expression L2 is as below

RE = (a+b)* (ab) (a+b)*



Using De-Morgan’s law for sets

(L1C U L2C)C = (L1C)C ∩ (L2C)C = L1 ∩ L2

Please check RE of L1 and L2 is correct.

Plz send the complate file .........thanks

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Please upload solution file thanks.

CS402 (Theory of Automata) Assignment No. 3 Solution Spring 2019

file plz 

CS402 Assignment No 03 Solution Spring 2019

CS402 Assignment No 03 Solution Spring 2019

solution ki samg nih lagy rahe .solution shae waley file upload kro

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