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Assignment No. 2 Dated:Jan 12, 18
Assignment No.2 of Operating System(CS604) has been uploaded on VULMS. Deadline of the assignment is Thursday, January 18, 2018.
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Brother how we solve the condition of Analyze that request P1 (1, 2, 1) can be granted or not?
Kia hum Available/Work ma 1,2,1 put karayn gayn?
For System to be in safe state for request 1,2,1
My Safe sequence is < P1, P3, P4, P5, P2 >
Please tell how your is Safe sequence is: P3 P4 P5 P1 P2?
P1 's need can be fulfilled in first step as Availabe is 3,3,2 an p1's need is
Needi = Needi – Request = (1, 3, 2) – (1, 2, 1) = (0, 1, 1)
Read Lecture No 28 from handouts. You will find the solution to assignment
Solution: Banker’s Algorithm P0 need0 = (7, 4, 3) If need0 ≤ Available if [(7, 4, 3) ≤ (3, 3, 2)] (false)
P0 need1 = (1, 2, 2) if needi ≤ Available if [(1, 2, 2) ≤ (3, 3, 2)]
P2 need2 = (6, 0, 0) if need2 ≤ Available if [(6, 0, 0) ≤(5, 3, 2)] (false) P4 need4 = (4, 3, 1) If need4 ≤ Available If [(4, 3, 1) ≤ (6, 4, 3)] P0 need0 = (7, 4, 3) if need0 ≤ Available if [(7, 4, 3) ≤ (7, 4, 5)] P2 need2 = (6, 0, 0) if need2 ≤ Available if [(6, 0, 0) ≤ (7, 5, 5)] P2 will execute. Safety Sequence =
guys please share the valid solution which is sadka jaria
AOA please koi question file upload kr de. mera account blck hai.
upload kr di ha bhai
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