Assignment # 6 CS609 has been uploaded. Its due date is 06 -02- 2013. Please discuss here about the assignment
Please read the following instructions carefully before submitting assignment:
It should be clear that your assignment will not get any credit if:
The objective of this assignment is to enhance your knowledge about;
What advantage and disadvantage do we get if Bytes per Sector used in a file system is too small/large? Your answer shall be in the following tabular format.
No. of Bytes per Sector is Small
No. of Bytes per Sector is Large
Let suppose we have to store files on a hard disk having sizes given as below.
840 Bytes, 1790 Bytes, 650 Bytes, 2470 Bytes and 2840 Bytes.
You have to choose an optimal size of sector on your disk which also referred as Bytes per Sector or Block Size. You have the choice to choose the Sector size only from typical values 512 Bytes, 1024 Bytes or 2048 Bytes. Do not make random guess, do some calculations and report them in your solution. Based on your calculations, answer the following questions with reasons stated briefly.
Question No.1: What Block size will you choose if the objective is to have optimal disk space utilization?
Question No.2: What Block size will you choose if the objective is to have reduced access time?
You are required to submit a single MS word file through LMS.
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den hlp us plzlllllll
koi tu hlp kr dy
Time to running out... shahid bro try to understand
sidha sidha solution upload ker dein g plzzzzzzzzzzzzzz q trsa trsa k jan nikalty hein ab time hi kitna reh gia hy koi duain lena chata he to help ker dey dukhi dil ko khush kren to dua bhi dil se niklti hy May GOD help them who will help us amin
help ker dein bhai ab sol de hi dein plzzzzzzzzzz time bht km hy light ka bhi pta ni
Thanks , Hammad
512 bytes block size is best because in that memory loss is least. You can use following formula to calculate memory unused space:
Unused space=Block Size-File Size
Afer putting the values in question i.e 1790, 650 etc one by on and then totaling tem for each case you will come to know that in case of 512 unused space is least so 512 byte size is best for optimum space utilization.
In this case 2048 byte size is best because it will inlvolve least number of acesses and hence fastest.
Acsesses in 2048=7
Accesses in 1024=10
Accesses in 512=19
So 2048 is best as it involves least number of accesess.
hammad bhai plz tell k how to calculate the access time. plz tell formula