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GDB # 2 Dated: May 25, 15

Dear Students,

A new GDB has been created and it will be open from May 26, 2015. Due date of the discussion board is May 28, 2015.

From today "Test Math Type” MDB will be closed and you will not allow posting your reply on regular MDB. 

Moreover a new functionality (Preview) has been added in GDB to verify that your post is correctly displaying. So before posting your comments you should first preview your post and if the equations are correctly displaying then you can post the comment. Remember once you post the comments on GDB then you cannot edit or repost your comment.


Differentiate the following function with respect to t.


Grading criteria will be as follows:

  1. If all the  derivatives are calculated correctly, you will get  25% marks
  2.     Moreover if you correctly apply chain rule, you will get 50% marks
  3. If there is calculation/simplification mistake in final calculation, you will get 75% marks
  4. If you express the final equation in terms of ‘t’ , you will get 100% marks

Note: It is mandatory to mention all necessary calculation steps to get full marks.

Views: 3397

Replies to This Discussion

use google chrome browser

Thnak u sooo much SAJIDA and alll frends for help n solution... :)

Mai try kr rha hun Post krny ki mgr preview sahi nai dy rha. Mai ne AMSLatex selec kia hai mgr phr b nai dy rha. Plz i need help immediately. 

use google chrome browser

Wohi use kr rha hun bhai.

Preview mai same as coded show krta hai.

kia ye answer correct hai?

I think it is \[96{t^5} - 12{\cos ^2} - 2\cos \sin {t^2} + 4\sin {t^4}\]

esko agy t kyle solve nahi karna kia?

Agay kesy solve krn? Give me some hints...

Find the derivative of each expression, beginning with 96t^5

e.g. d/dt 96t^5

Jnab os k baad dobara derivative nai lea jata. Wrna wo double derivative ho jay ga. Yeho to dw/dt tha.. I hope you got my point.


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