Mth 101 All Current Mid Term Papers Spring 2013 (25 May 2013 ~ 06 June 2013) at One Place - Virtual University of Pakistan 2021-10-18T17:52:26Z https://vustudents.ning.com/forum/topics/mth-101-all-current-mid-term-papers-spring-2013-25-may-2013-06?groupUrl=mth101calculusandanalyticalgeometry&commentId=3783342%3AComment%3A2798871&groupId=3783342%3AGroup%3A59539&feed=yes&xn_auth=no Q: Find the equation of the t… tag:vustudents.ning.com,2013-06-01:3783342:Comment:2798871 2013-06-01T04:29:15.841Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p>Q: Find the equation of the tangent line y=f(x)=x^3 at point (0,0)</p> <p>Q: find dy/dx if y =</p> <p>Q: find dy/dx by product rule if y =</p> <p>Q: find dy/dx when</p> <p>Q: determine epsilon-delta argument  show that (asa hi question tha)</p> <p>Q: Find the equation of the tangent line y=f(x)=x^3 at point (0,0)</p> <p>Q: find dy/dx if y =</p> <p>Q: find dy/dx by product rule if y =</p> <p>Q: find dy/dx when</p> <p>Q: determine epsilon-delta argument  show that (asa hi question tha)</p> mymth10126may2013 tag:vustudents.ning.com,2013-05-31:3783342:Comment:2795112 2013-05-31T13:16:49.043Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p><strong>mymth10126may2013</strong></p> <p><strong>mymth10126may2013</strong></p> All solved MTH101 past midter… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2783627 2013-05-29T17:52:33.132Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p><span>All solved MTH101 past midterm papers in one file</span><span><br/><br/><br/></span></p> <p><span>All solved MTH101 past midterm papers in one file</span><span><br/><br/><br/></span></p> All solved MTH101 past midter… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2783617 2013-05-29T17:50:01.646Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <h1>All solved MTH101 past midterm papers in one file</h1> <h1>All solved MTH101 past midterm papers in one file</h1> Find the equation of the line… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2783314 2013-05-29T17:13:13.423Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p><strong>Find the equation of the line that passes through (6,5) and (-3, -1).?</strong></p> <p><strong>First you want to find the slope. The formula is:</strong></p> <p><strong>y2 - y1 (divided by)</strong> <br></br><strong>x2 - x1 (the numbers are sub 1 and sub 2, not exponents)</strong></p> <p><strong>in the first ordered pair (x1, y1) is (6,5). the second (x2, y2) is (-3, -1)</strong></p> <p><strong>now fill in the formula.</strong></p> <p><strong>y2 is -1. y1 is 5. So the numerator is -1…</strong></p> <p><strong>Find the equation of the line that passes through (6,5) and (-3, -1).?</strong></p> <p><strong>First you want to find the slope. The formula is:</strong></p> <p><strong>y2 - y1 (divided by)</strong> <br/><strong>x2 - x1 (the numbers are sub 1 and sub 2, not exponents)</strong></p> <p><strong>in the first ordered pair (x1, y1) is (6,5). the second (x2, y2) is (-3, -1)</strong></p> <p><strong>now fill in the formula.</strong></p> <p><strong>y2 is -1. y1 is 5. So the numerator is -1 minus 5. Which is -6.</strong></p> <p><strong>x2 is -3. x1 is 6. So the denominator is -3 minus 6. Which is -9.</strong></p> <p><strong>So our slope is -6/-9 which can be simplified to 2/3.</strong></p> <p><strong>NOW. You know the slope is 2/3. Now you must find a line with this slope that runs through those points (either set of points will work).</strong></p> <p><strong>y - y1 = 2/3 (x - x1).</strong><br/><strong>Fill in for y1 and x1 with either set of points (but be consistent. if you use from the first set for x, you must use from the first set for y).</strong></p> <p><strong>We'll use (-3, -1)</strong><br/><strong>y - -1 = 2/3 (x - -3)</strong></p> <p><strong>When subtracting a negative, you add. So:</strong></p> <p><strong>y + 1 = 2/3 (x + 3)</strong></p> <p><strong>Now distribute 2/3.</strong></p> <p><strong>y + 1 = 2/3x + 2. (2/3 times 3 is 2)</strong></p> <p><strong>now subract 1 from both sides.</strong></p> <p><strong>y = 2/3x + 1</strong></p> What are the critical points… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2783474 2013-05-29T17:13:04.677Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p><strong>What are the critical points of f(x)= x^3+2x^2-4x+5?</strong></p> <p><strong>to find the critical points of a function, we need to find the first derivative and equal it to zero as the following:</strong></p> <p><strong>f(x) = x^3+2x^2-4x+5</strong></p> <p><strong>f ' (x) = 3x^2 + 4x - 4 ===&gt;equal it to zero</strong></p> <p><strong>0 = 3x^2 + 4x - 4</strong></p> <p><strong>-b +/- [ sqrt( b^2 - 4*a*c ) ] / [ 2a ]</strong></p> <p><strong>-4 +/- [ sqrt( 4^2 - 4*3*-4 ) ] / [ 2*3…</strong></p> <p><strong>What are the critical points of f(x)= x^3+2x^2-4x+5?</strong></p> <p><strong>to find the critical points of a function, we need to find the first derivative and equal it to zero as the following:</strong></p> <p><strong>f(x) = x^3+2x^2-4x+5</strong></p> <p><strong>f ' (x) = 3x^2 + 4x - 4 ===&gt;equal it to zero</strong></p> <p><strong>0 = 3x^2 + 4x - 4</strong></p> <p><strong>-b +/- [ sqrt( b^2 - 4*a*c ) ] / [ 2a ]</strong></p> <p><strong>-4 +/- [ sqrt( 4^2 - 4*3*-4 ) ] / [ 2*3 ]</strong></p> <p><strong>-4 +/- [ sqrt( 16 + 48) ] / [ 6 ]</strong></p> <p><strong>-4 +/- [ sqrt( 64) ] / [ 6 ]</strong></p> <p><strong>[ -4+/- 8 ] / 6 =====&gt; [ -4+8 / 6 ] = 2/3 =====&gt; &amp; [ -4-8 / 6 ] = -2 ( critical points )</strong></p> Raheel thanks for sharing  At… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2782201 2013-05-29T13:50:41.307Z + M.Tariq Malik https://vustudents.ning.com/profile/malik12 <p><a class="fn url" href="http://vustudents.ning.com/group/mth101calculusandanalyticalgeometry/forum/topic/listForContributor?user=3ml8a8mum38at">Raheel</a> thanks for sharing <img src="http://www.bkserv.net/images/Smile.gif"></img></p> <p><b>Attention Related Mid Term papers Spring 2013:</b> All Fellows You don’t need to go any other site for current Mid Term papers Spring  2013, Because All discussed data/sharing of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t…</p> <p><a href="http://vustudents.ning.com/group/mth101calculusandanalyticalgeometry/forum/topic/listForContributor?user=3ml8a8mum38at" class="fn url">Raheel</a> thanks for sharing <img src="http://www.bkserv.net/images/Smile.gif"/></p> <p><b>Attention Related Mid Term papers Spring 2013:</b> All Fellows You don’t need to go any other site for current Mid Term papers Spring  2013, Because All discussed data/sharing of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t waste your precious time with different links.</p> agar concept theak ho to pape… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2781943 2013-05-29T12:26:12.552Z Raheel https://vustudents.ning.com/profile/Raheel850 <p>agar concept theak ho to paper easily solve ho jata hay.</p> <p>remember me in ur prayers</p> <p>Mostly question on concept basis not from past paper.</p> <p></p> <p>agar concept theak ho to paper easily solve ho jata hay.</p> <p>remember me in ur prayers</p> <p>Mostly question on concept basis not from past paper.</p> <p></p> 1) Limt sinx/x=? 2)Cos (8x+5)… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2781881 2013-05-29T12:24:29.089Z Raheel https://vustudents.ning.com/profile/Raheel850 <p>1) Limt sinx/x=?</p> <p>2)Cos (8x+5)</p> <p>3)tan 5-3x option sy select karna tha</p> <p></p> <p></p> <p>1) Limt sinx/x=?</p> <p>2)Cos (8x+5)</p> <p>3)tan 5-3x option sy select karna tha</p> <p></p> <p></p> mth 101 midterm paper 29.05.2… tag:vustudents.ning.com,2013-05-29:3783342:Comment:2781874 2013-05-29T12:19:06.456Z Raheel https://vustudents.ning.com/profile/Raheel850 <p>mth 101 midterm paper 29.05.2013 time 3:30</p> <p>Only 4 to 5question from past papers and remaning from book. Paper was conceptual so read properly book.</p> <p>mth 101 midterm paper 29.05.2013 time 3:30</p> <p>Only 4 to 5question from past papers and remaning from book. Paper was conceptual so read properly book.</p>