We have been working very hard since 2009 to facilitate in your learning Read More. We can't keep up without your support. Donate Now.

www.vustudents.ning.com

 www.bit.ly/vucodes + Link For Assignments, GDBs & Online Quizzes Solution www.bit.ly/papersvu + Link For Past Papers, Solved MCQs, Short Notes & More

# MTH100 Assignment 2 Fall_2015

Please discuss here for the assignments..

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

Views: 495

Attachments:

### Replies to This Discussion

try to do by your own....

Q # 3

Solution:

There are 10 elements in the word"bookkeeper".
o= 2, k=2 ,e=3.

number of permutations is:

P = 10! / (2! 2! 3!)

10! = 3,628,800
(2! 2! 3!) = 24

So, P= 10! / (2! 2! 3!) = 151,200 ANSWER!

Q # 1

Just change the value as per question

Find the sum of the first 50 terms of an arithmetic series with a = 28 and d = -4

Solution: We need to know n, a, and a50. n= 50, a = 28, d = -4. The formula is Sn = n/2(2a + (n-1)d) So, S50 = 50/2(2(28) + (50-1)(-4)) = 25(56 + 49 (-4)) = 25(56 – 196) = 25(-140) = -3500

## Latest Activity

1 hour ago
2 hours ago
2 hours ago
++ ! !!*ARhum* ! ! !++ posted discussions
2 hours ago

1

2

3

## HELP SUPPORT

This is a member-supported website. Your contribution is greatly appreciated!