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MTH101 Calculus And Analytical Geometry GDB Solution & Discussion 

For a functiona pointand a positive numberFind

                               

Moreover find a number such that 
 Note:

Please follow the following methodology to find 

  • Solve the inequalityto find an open intervalcontainingon which the inequality holds for all.
  • Find a value ofthat places the open intervalcentered atinside the interval.The inequality will holds for allin this 


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is that true?

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MAth 101 GDB2 Solution in Mathtype


\[\begin{gathered}
l = \mathop {\lim }\limits_{x \to x^\circ } f(x) \hfill \\
l = f(x^\circ ) \hfill \\
l = f(x^\circ ) = (3 - 2xo) \hfill \\
l = f(x^\circ ) = 3 - 6 \hfill \\
l = f(x^\circ ) = - 3 \hfill \\
|f(x) - l| < 6 \hfill \\
|3 - 2x + 3| < 0.002 \hfill \\
|3 - 2x - ( - 3)| < 0.02 \hfill \\
|3 - 2x + 3| < 0.02 \hfill \\
|6 - 2x| < 0.02 \hfill \\
- 0.02 < |6 - 2x| < 0.02 \hfill \\
3.01 < x < 2.99 \hfill \\
\partial = ? \hfill \\
0 < |x - x^\circ | < \partial \hfill \\
|x - x^\circ | < \partial \hfill \\
- \partial < |x - 3| < \partial \hfill \\
- \partial + 3 < |x| < \partial + 3 \hfill \\
- \partial + 3 = 2.99 \hfill \\ 
\end{gathered} \]

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any one have mth 101 lecture 12-15 practice questions solution plz post it

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