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MTH101 Current MID Term Papers Fall 2012 Date: 08-December-2012 to 19-December-2012
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+ Click Here to Search (Looking For something at vustudents.ning.com?) + Click Here To Join (Our facebook study Group)Please Share your Current Papers Questions/Pattern here to help each other. Thanks
waiting...............
AOa to all.any one share current paper hare.
w Salam. No brother nobody share. I think student just interested in CS 101 because we can found a lot of help about CS 101 on this website.
80% of my mth101 exam covered:
1. continuity of functions
2. chain rule
3. and derivatives of trignometric functions
And the rest 20% from the previous exams.
Work hard and Best of Luck to all of you guys!
Hayder Saleem Thanks for sharing ur paper
Note for All Members: You don’t need to go any other site for current Mid Term papers fall 2012, Because All discussed data/sharing of our members in this discussion are going from here to other sites. You can judge this at other sites yourself. So don’t waste your precious time with different links.
Thaaaaaaaaaaaaaaanx a lot sharing paper
Thaaaaaaaaaaaaanx alot sharing paper
Today’s Current Midterm Paper
Total Questions = 26
Total MCQ = 20
2 Questions of 2 Marks
2 Questions of 3 Marks
2 Questions of 5 Marks
Find the point of discontinuing of the given function: 2 Marks
f (x) = 3x + 1
X2-7x+12
Find dx at (-5,6) if x2 + y2 =0 2 Marks
dy
Determine whether lim 1 – cos |x| exists or not? 3 Marks
x−>0 x
if f '(t)= 2t then find the intervals on which the function f(t) increasing and decreasing? 3 Marks
Use an epsilon-delta argument to prove that 5 Marks
lim (3x + 5) = 35
x−>0
if f(x) = x -5x+6 then find the intervals where the function is concave up and concave down. 5 Marks
in the epsilon delta argument limit x->10 not "0"????m i ryt bcz "0" se ye solve ni ho raha?????
>>>>>i want some help/p>
please koi math ki tyari ka assan hal bta day taa k understanding ho jay question ki or paper b acha ho jay plz ma bht tens hoon any one plzzz tuseday ko paper hai.... m waitnig
mth ki teyare ka koi asan tareqa ni hy bhaee,
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