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            Total marks: 10

             Lecture # 1 to 8  

Due date: October 25, 2011


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Question 1:


Convert the given spherical coordinates to rectangular and cylindrical coordinates.





Question 2:


Determine whether the following limit exists





Question 3:


Check the continuity of function at (0, 0)




Question # 4


Calculate  by using chain rule of differentiation.

Where   and



Question 5:


Calculate the value of  if 

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Replies to This Discussion

Please send MTH301 Q3. Solution if you have done it and sure that it's correct.


Dear Mr. Shahbaz


Please send me Q3. pLZZZZZZZ

the answer which has already been posted by me is true

which one i can't find it. Please send it's link

@shehbaz the Q5 when ve take the double partial derivative by keeping y constant then "y" becomes zero n only left is "x" so how can we put(1,1) values??? as there is only x ????

if there is no y, then simply put x=1.

when y become zero(0) then 6x^2 will be left then put the value of x and answer will be 6 


[Image: 2a8hoaq.jpg]

final answer is correct i.e. function is indeed continuous at (0,0) BUT they way limit has been calculated is WRONG. 0/0 is not equal to zero. It is an indeterminate form. To calculate the limit, we will have to approach from 3 different paths which are x=0, y=0, and y=x

your question is wrong my brother

to whom you said that?

i think u r right calculus lover

why any one is not calculating the third point function along the line y=x?


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