Share the Idea Solution
Total marks: 10
Lecture # 1 to 8
Due date: October 25, 2011
DON’T MISS THESE Important instructions:
Question 1:
Convert the given spherical coordinates to rectangular and cylindrical coordinates.
Question 2:
Determine whether the following limit exists
Question 3:
Check the continuity of function at (0, 0)
Question # 4
Calculate by using chain rule of differentiation.
Where and
Question 5:
Calculate the value of if
Tags:
Please send MTH301 Q3. Solution if you have done it and sure that it's correct.
thanks
Dear Mr. Shahbaz
Please send me Q3. pLZZZZZZZ
bc080401773@vu.edu.pk
the answer which has already been posted by me is true
which one i can't find it. Please send it's link
@shehbaz .....in the Q5 when ve take the double partial derivative by keeping y constant then "y" becomes zero n only left is "x" so how can we put(1,1) values??? as there is only x ????
if there is no y, then simply put x=1.
when y become zero(0) then 6x^2 will be left then put the value of x and answer will be 6
final answer is correct i.e. function is indeed continuous at (0,0) BUT they way limit has been calculated is WRONG. 0/0 is not equal to zero. It is an indeterminate form. To calculate the limit, we will have to approach from 3 different paths which are x=0, y=0, and y=x
your question is wrong my brother
to whom you said that?
i think u r right calculus lover
why any one is not calculating the third point function along the line y=x?
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