In a hospital, births occur randomly at an average rate of 2 births per hour. Calculate the probability of observing
1. 3 births in a given hour at the hospital.
2. No birth in a given hour at the hospital."
Opening Date of Graded Discussion Board:
Friday, August 14, 2015 at 12:01 a.m.
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Yar Sohail Bhayi please solution file he upload kr dein. ya phir handouts ka page no bta dein.
μ=is an average rate of value.
x =is a poison random variable.
e =is the base of logarithm (e=2.718)
I): 3 births in a given hour at the hospital.
Poisson random variable (x) = 3
Poisson Probability: P(X = 3)
0.18045
II): No birth in a given hour at the hospital.
Poisson Probability: P(X = 0)
0.1353
μ=is an average rate of value.
x =is a poison random variable.
e =is the base of logarithm (e=2.718)
I): 3 births in a given hour at the hospital.
Poisson random variable (x) = 3
Poisson Probability: P(X = 3)
0.18045
II): No birth in a given hour at the hospital.
Poisson Probability: P(X = 0)
0.1353
100% correctsee handout page no. 280 for reference
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“In a hospital, births occur randomly at an average rate of 2 births per hour. Calculate the probability of observing
μ=is an average rate of value.
x =is a poison random variable.
e =is the base of logarithm (e=2.718)
I): 3 births in a given hour at the hospital.
Poisson random variable (x) = 3
Poisson Probability: P(X = 3)
0.18045
II): No birth in a given hour at the hospital.
Poisson Probability: P(X = 0)
0.1353
μ=is an average rate of value.
x =is a poison random variable.
e =is the base of logarithm (e=2.718)
I): 3 births in a given hour at the hospital.
Poisson random variable (x) = 3
Poisson Probability: P(X = 3)
0.18045
II): No birth in a given hour at the hospital.
Poisson Probability: P(X = 0)
0.1353
how u calculated ?????
3 births in a given hour at the hospital.
Poisson random variable (x) = 3
Poisson Probability: P(X = 3)
0.18045
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mth302 gdb 2 solution 2015
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