Under what conditions the solution of the first order ordinary differential equation exist?
Furthermore, without solving the following initial value problem determine the interval in which the solution is certain to exist.
Opening Date: August 13, 2014 at 12:01 AM
Closing Date: August 18, 2014 at 11:59 PM
Post your discussion only on the provided Graded Discussion Board forum and not on regular MDB forum.
MathType equation is not supported directly in this forum. If you want to use any MathType equation then write the equation on the
and then copy and paste the image. However any mathematical equation is not needed to answer this question. You can write the interval in plain text.
Zero marks will be awarded to irrelevant discussion or to those which are copied from website or any other source.
Do not post your discussion more than once.
Be careful about the date and time limitation as due date will not be extended for anyone.
No post will be accepted through e-mail.
for question 2 .... see the link below.....
solve kuch bhi nhi karna... bus interval likhna hai
what is the interval?
P(x) = tan(x) that is continuous every where except (Pi/2 , 3Pi/2 , 5Pi/2 and so on )
Q(x) = sin(x) that is continuous every where....
y=0 where x = Pi/4
so interval would be (-inf .+inf)
Question 1 me IVP and BVP ae ga..... mere Khayaal se.....
Q k 2nd part me IVP ka hi zikr hai saath
Abdul rauf bhai agr ap solution up load ker dey to every student submit. i think that ap ne solve ker leya hy. please brother time very short.
bhai yar solution to kuch min k liye share kr do
please upload solution yarrrrrrrrr plz
Pls upload the solution in the students interest....
pls pls pls /...........................
plzzzz 4rnd koi solution upload kar do pljjjjjjj koi idea
Allah ka name le ker submit ker do jasa b kia hy.
lagta hae kisi nay kiya he nhiiiii