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Discussion Topic:

Under what conditions the solution of the first order ordinary differential equation exist?

Furthermore, without solving the following initial value problem determine the interval in which the solution is certain to exist.



Opening Date: August 13, 2014 at 12:01 AM

Closing Date:  August 18, 2014 at 11:59  PM

 

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Replies to This Discussion

plz solution upload kr do

time bht kam rh gya hai 

agr aap upload nai kr skty to wesy msg kr dain mujy..

plz.....

msg kidr karo ga....................

chat main aapko mery msgs recv ho rhy hain na

whan kr do aap plz

Nawaz sharif na bano , karna hai to karo warna inkar kar do. takay koi aur hal nikalain

o mian saaaab jaaaan dayo................

please share soluton 

The axes of a two-dimensional Cartesian system divide the plane into four infinite region called quadrants each bounded by two half’s. So P(x) = Tan(x) that is continuous every where except the π/2, 3π/2, 5π/2 and so on in a quadrant and Q(x) = Sin(x) that is continuous every where y = 0 where x = π/4. It also has a certain solution on t-interval containing t0. 

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