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hahah Lagta hy saeed Bhai aap ka paper nhi hua

Kyon keh aap ny paper share hi nhi kiya

Aap ka paper to 1st September ko tha na

Today’s Paper

Total Question = 52

MCQs = 40

Subjective = 12

Aik Question Graph ka tha

Aik Question Dual our primal ka tha jaisa assignment main tha    (5 M)

Annual Cummulative cost  Wala Question tha

UV Multiplier Wala Sawal tha

Least cost wala question tha lakin ajeeb tha solve hi nhi ho rha tha halankeh mujhy least cost method aata bhi tha

Baqi question past sy thy yeh waly

A company cost Rs. 500 operations and maintenance costs are zero for the first year and increased by Rs. 100 every year. If money is worth 5% every year, calculate present worth (P(r)) for each year. The resale value of the machine is negligibly small.

for each year increase in money = 5%

means to say that company significes 105 ruppes every year the company capital must be increaing as 105 * 500

 0 5 2 1 1 6 2 1 5 5 2 7 2 4 3 7 7 5 5 10

To find optimality condition we use UV multiplier process

Find

1. U2+V2
2. U3+V3

The cost of a new machine is Rs. 5000. The maintenance cost during the nth year is given by Mn = Rs.500 (n-1), where n=1, 2, 3… If the discount rate per year is 0.05, determine discount factor (vn-1) for each year.

Solution:

M = 5000

Mn = 500 (n-1)

V = 0.05

(vn-1) = ?

 Nth year Mn (vn-1) 1 0 1.00 2 500 0.05 3 1000 0.0025 4 1500 0.000125

Or

 Nth year (vn-1) 1 1.00 2 0.05 3 0.0025 4 0.000125

Determine whether the following Transportation model has initial feasible solution?

 D1 D2 D3 D4 Supple Q1 x11 x12 x13 x14 6 Q2 X21 X22 X23 X24 8 Q3 X31 X32 X33 X34 10 Demand 4 6 8 6

Solution:

The transportation problems can berepresented mathematically as a linear programming model. The

Objective function in this problem is to minimize the total transportation cost given by

Z = c11x11+ c12x12+ ... + cmnxmn

Subject to the restrictions:

Row restrictions:

x11 + x12 + x13 + x14 = 6

x21 + x22 + x23 + x24 = 8

x31 + x32 + x33 + x34 = 10

Column restrictions:

x11 + x21 + x31 + x41 = 4

x12 + x22 + x32 + x42 = 6

x13 + x23 + x33 + x43 = 8

x14 + x24 + x34 + x44 = 6

And

x11 + x12 + x13 + x14≥0

It should be noted that the model has feasible solutions only if

a1 + a2 + a3 + a4 = 4+6+8+6

Or

=

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