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Question 3:

Correct option is
c) The total amount of momentum before and after the collision is same.

Add some explanation.

plzzzz help krin phy101 k assignment main correct solutionn upload krin

:(

plz send me the assignment solution phy101

plzzzzzzzz help me saif bahi in question no 1, 2 and 5 

plz send the assignment  solution of phy101.

plz send me the slution of phy101

saif bhai ji plzzzzz......... question no 1,2 or 5 k formulas share kar dain plzzzzzzzz....... bohat kaam time rah gaya hai assignment submit karwane ka ..... plzzzzz help me.....  

Any idea for question 5?

give the idea of question no.1 also and 5 too thanks

 

Net force = Tension - Force of gravity = mass * acceleration

a=3.5 and mass=3.50

T=F=12.25

 

Is main Kinetic friction kahn gy

Question: 01
Time of flight=1.60s
Range=75cm
Time of flight = 2•V•sinΘ/g = 1.60 s ← #1 
range = (V²sin(2Θ))/g = 0.75 m ← #2 
Divide #2 by #1: 
0.75m / 1.6s = Vsin(2Θ) / 2sinΘ 
But sin(2Θ)= 2sinΘcosΘ, so 
0.47 m/s = VcosΘ ← initial horizontal component -- #3 
rearranges to V = 0.47m/s / cosΘ

Now plug that into #1: 
2 * (0.47m/s / cosΘ) * sinΘ / 9.8m/s² = 1.6 s 
0.096s * tanΘ = 1.6s 
tanΘ = 16.7

Now multiply both sides of #3 by tanΘ = 16.7 
0.47m/s * 16.7 = VcosΘ * tanΘ = VsinΘ 
VsinΘ = 7.8 m/s ← vertical component



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