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# phy101 assignment 2 spring 2014 due date 26-5-2014

Assignment 2: (Spring 2014)
PHYSICS (PHY101)
TOTAL MARKS: 30
Due Date: 26/05/2014
DON’T MISS THESE Important instructions:

To solve this assignment, you should have good command over first 16 lectures.
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Don’t wait for the last date to submit your assignment.
Question. No: 1

A  lift  is  filled  with  patients  has  a  total  mass  of  2055  kg.  As  the  lift  begins  to  go  up,  the
acceleration  is  0.75  m/s
2
.  What  is  the  tension  in  the  rope  that  is  lifting  the  lift?  Validate  your
solution as well.                                                                                                                   Marks 5
Question. No: 2

A man pushes a lawnmower with a force of 170 N at an angle of 37° down from the horizontal.
The lawn is 12.0 m wide and requires 16 complete trips across and back. How much work does
he do?                                                                                                                                   Marks 6

Question. No: 3

A bus’s tire rotates at an initial angular speed of 20.5 rad/s. The driver accelerates, and after 4.5 s
the tire’s angular speed is 29.0 rad/s. What is the tire’s average angular  acceleration during the
4.5 s time interval?                                                                                                               Marks 7
Question. No: 4

An object’s momentum depends upon the object’s

a)  mass, speed and acceleration.
b)  mass, speed and direction of motion.
c)  speed and acceleration.
d)  velocity and direction of motion.
e)  mass and acceleration.

Write the reason of your above selected choice as well.                                          Marks 3+3 = 6

Question. No: 5

You drive a nail horizontally into a wall, using a 0.52 kg hammerhead. If the hammerhead is
moving horizontally at 4.5 m/s and in one blow drives the nail into the wall a distance of 2.9 cm,
determine the average force acting on

(b) the nail                                                                                                                        Marks = 6

::::::::::::::::::::::::::: Wish you good luck::::::::::::::::::::::

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### Replies to This Discussion

Koi idea solution ho to .......

Assignment Done.....

yar koi last q kara 2 plzzzzzzzzzzzzzz

koi to assignment solution do

are you sure this is right answer

yaaaaaaaaaaaaaaaaaaaaaarrrrrrrrrrrrrrrrrr koi dai do na solution phy101???

in question no.2

use formula w=fdcosᶿ

angle and f are given in the question.. u can find D which is the total distance by multiplying total trips and width i.e 16x12=192.

put all the three values in the formula n just calculate

Two forces work on the elevator: gravity ( m g) in the direction of the acceleration, and T, the tension in the cable, in the direction opposite to the acceleration. That, and Newton's second law, gives

m g - T = m a

So

T = m ( g-a)
= 1000 kg* (9.8 m/s^2 - 1.8 m/s^2) = 8000 N

yes you are right

koi last question ki hint day day plz.

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