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Replies to This Discussion

Please Someone Help In This

mere b help ker dy koi mai to 1st ques pe he atak gai hun

In my opinion, first question can be solved by this formula F= qv *B sin teta

q= proton = 1.6*10^-19

v= speed

sin teta = angle

T= B

 

Question NO 1:

Answer 

q=1.6*10^-19 this is charge on proton 

v= 3.00*10^6

angle = sin 37 degree = 1.601

B= 0.300

F= qv*B sin teta.  Now puting the value in this formula you can easily find the answer  

Question no 3 

Answer: click the below link to find you question answer .

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/forwir2.html#c1

Mera Bhi haal Kuch Aesa Hi Hai.. :D :D :D

First Question me 2 things describe krni hain 1.magnitude 2, accelaration

Agar a find krna hai to us k liye formula f=ma lgy ga mean a=f/m lkn hmary pas speed or magnetic field di hui hai. So think Guys What to do tomorrow is the last day....

I Have got the answer of the 2nd question.... :)

hm u are right in my first question solution I have F= 865.10^-16

brother's gives your idea for the second question.... what I do with that?

The changing magnetic field in the coil induces voltage. In this way, information sotred magnetically on the disk is converted to electric signals.

This is the answer of q.2

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