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PHY101 Physics Assignment no 01 solution and discussion due date 27-11-2014

Assignment 1: (Fall 2014)
PHYSICS (PHY101)
TOTAL MARKS: 25
Due Date: 27/11/2014
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Question. No: 1
A set of frictionless wheels are attached to the bottom of a box, which is then measured and found to have a mass of 6.0kg. The box is placed on the floor, and a student of Physics uses a brief horizontal force of 150N to push the box sideways, after which the box rolls across the floor with constant velocity. How much Work does the floor do on the box as it rolls along?
Marks 6
Question. No: 2
A student of Physics with a mass of 60Kg performs an experiment by taking a scale into an elevator, setting it into floor, and standing on it. At first the scale indicates a weight of about 600Newtons, but then the elevator starts to accelerate downwards at 5m/s2.Calculate the value of weight indicated on the scale during this period of acceleration?
Taking acceleration due to gravity (g) = 10m/s2. Marks 5
Question. No: 3
An astronaut standing on the moon holds a large, heavy rock and a small, light stone, and then releases them from the same height. Which object reaches the moon‘s surface first?
Note: Select the best choice given below according to your best of knowledge, and also write the reason of your selected choice as well.
a) The rock, because it‘s heavier and accelerate faster
b) The rock, because it has a greater force of gravity acting on it.
c) The stone, because there is less air frication acting on it.
d) They reach on the surface at the same time because their acceleration due to gravity is equal.
e) Both the rock and stone will just float there when released-there is no gravity on the moon.
Marks 3+4 = 7
Question. No: 4
A large 1.5Kg book rests on the surface of a rough table, and a horizontal force of 60N (to the right in the sketch shown above) is applied to it. If a frication force of 35Newtons opposes the motion of the book, determine the value of acceleration with which book will accelerate?
Marks 7
::::::::::::::::::::::::::: Wish you good luck::::::::::::::::::::::

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### Replies to This Discussion

sana siso aik chz hai distance kahan se aya n jb already we know the mass value to again q find ki???

question 1 solution

w=mg

d=mg/f

6.0*9.8/150

58.8/150

d=0.392

w= 150*0.392

w=58.8            d= w/f

Where w = work; not weight

apka solution ghalat hai rastee

page 11 frm txtbook n point 12 read it apko smjh ajaige

This is wrong rastee

Q.No 2

F gravity = mg

g=10 m/s2

a=5 m/s2

F acceleration = ma

Hence F net = m (g-a) =60(10-5)       = 60*5

net = 300 Newton

q mae to600 N b hai us ka kia kia apne??????? wo kaha gaya

olution Question No.01:-

Weight = mg

Distance = mg/F

=6.0*9.8 /150

= 58.8/150

Distance = 0.392

W= 150*0.392

W = 58.8 J

kea ye sahe ha

ye thk h??

Solution 4: mass=1.5 kg

Force applied=60 N

Frictional force=35 N

Acceleration = net force/mass

Net force=?

Net force= force applied + frictional force

= 60N + 35N =95 N

Acceleration =f/m

= 95/1.5 =63.33 m/s2.

correct me if i am wrong.

koi to bta dy      