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PHY101 Physics Assignment no 01 solution and discussion due date 27-11-2014

PHY101 Physics Assignment no 01 solution and discussion due date 27-11-2014

Assignment 1: (Fall 2014)
PHYSICS (PHY101)
TOTAL MARKS: 25
Due Date: 27/11/2014
DON’T MISS THESE Important instructions:
To solve this assignment, you should have good command over first 10 lectures.
Upload assignments (Microsoft word) properly through LMS, (No Assignment will be accepted through email).
Write your ID on the top of your solution file.
All students are directed to use the font and style of text as is used in this document.
Don’t use colorful back grounds in your solution files.
Use Math Type or Equation Editor etc for mathematical symbols.
Write to the point and avoid from unnecessary explanation. Don’t copy/paste from internet or any other source.
This is not a group assignment, it is an individual assignment so be careful and avoid copying others’ work. If some assignment is found to be copy of some other, both will be awarded zero marks. It also suggests you to keep your assignment safe from others. No excuse will be accepted by anyone if found to be copying or letting others copy.
Don’t wait for the last date to submit your assignment.
Question. No: 1
A set of frictionless wheels are attached to the bottom of a box, which is then measured and found to have a mass of 6.0kg. The box is placed on the floor, and a student of Physics uses a brief horizontal force of 150N to push the box sideways, after which the box rolls across the floor with constant velocity. How much Work does the floor do on the box as it rolls along?
Marks 6
Question. No: 2
A student of Physics with a mass of 60Kg performs an experiment by taking a scale into an elevator, setting it into floor, and standing on it. At first the scale indicates a weight of about 600Newtons, but then the elevator starts to accelerate downwards at 5m/s2.Calculate the value of weight indicated on the scale during this period of acceleration?
Taking acceleration due to gravity (g) = 10m/s2. Marks 5
Question. No: 3
An astronaut standing on the moon holds a large, heavy rock and a small, light stone, and then releases them from the same height. Which object reaches the moon‘s surface first?
Note: Select the best choice given below according to your best of knowledge, and also write the reason of your selected choice as well.
a) The rock, because it‘s heavier and accelerate faster
b) The rock, because it has a greater force of gravity acting on it.
c) The stone, because there is less air frication acting on it.
d) They reach on the surface at the same time because their acceleration due to gravity is equal.
e) Both the rock and stone will just float there when released-there is no gravity on the moon.
Marks 3+4 = 7
Question. No: 4
A large 1.5Kg book rests on the surface of a rough table, and a horizontal force of 60N (to the right in the sketch shown above) is applied to it. If a frication force of 35Newtons opposes the motion of the book, determine the value of acceleration with which book will accelerate?
Marks 7
::::::::::::::::::::::::::: Wish you good luck::::::::::::::::::::::


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Replies to This Discussion

Please Discuss here about this assignment.Thanks

Our main purpose here discussion not just Solution

We are here with you hands in hands to facilitate your learning and do not appreciate the idea of copying or replicating solutions.

sana thanks for sharing .keep it up 

thnks :)

book pg:11 n us mai 11 point aik dafa study kern may b apko idea mil jai koi us se hme b help mil jai 

Dear Students Don’t wait for solution post your problems here and discuss ... after discussion a perfect solution will come in a result. So, Start it now, replies here give your comments according to your knowledge and understandings....

A large 1.5Kg book rests on the surface of a rough table, and a horizontal force of 60N (to the right in the sketch shown above) is applied to it. If a frication force of 35Newtons opposes the motion of the book, determine the value of acceleration with which book will accelerate? 

                                                                          Answer 

Given data

Mass=M=1.5kg

Force=Fapplied=F1=60N

Force=Ffrictional=F2=35N

To find

Fnet=F=?

Acceleratio=a=?

We know that

F=F1-F2

a=fnet/mass

solution

 

F= F1-F2

=60-35

=25N

Fnet=F=25N

Now

a=F/mass

=25/1.5

=16.67m/s2

Acceleration=a=16.67m/s2 

correct or not 

brother tariq malik  question 1 thora difficult hay b/c question no:1 main distance ke value nahee de huie .

please koiye help kerday kay iska work kaisay calculate hoga??

work = force x distance  = mass x gravity x distance.

Question 1:

A set of frictionless wheels are attached to the bottom of a box, which is then measured and found to have a mass of 6.0kg. The box is placed on the floor, and a student of Physics uses a brief horizontal force of 150N to push the box sideways, after which the box rolls across the floor with constant velocity. How much Work does the floor do on the box as it rolls along?

bro shabka khan lec:7 pg:19 per likha hwa hay formula:

Work = mass x acceleration x distance

   W = Fd = mad

a kasy find karo gy?? no time is given, no acceleration is given?

Bro ! Distance kese find karen gay

work = force x distance  = mass x gravity x distance.

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