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# sta301 1st assignment solution by ash

if u find any mistake so plzzzzz tell

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ash hmm gud ....

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secnd qstion k a part ma ap ko medin ka formula dekan ha

median=X childa =l+h/f(n/2-C.F)

is ma

l= the lower class boundary of the medain class(n/2)

h=the class intrval size of the median class

f = the class frequncy of tmedian class

n=sigma f=total frequncy

C.F=the cumulative frequenchy preceding the medin class cumulativ freq

c.b              f                     c.f

145-150        4                 4

150-155        6                  10

155-160       28                 38

160-165      58                    96

165-170     64                  160

170-175    30                  190

toal           190

median class or the modal class = (n/2)th=190/2=95 th (to see in c.f)

so the medain r modal class is 160-165         58                    96

by putng the valus in formula

medain = 160 +5/58(95-38)

=160+5/58(57)

=164.9138

thnxx

Good Job Thanks

question 1 ki classes mein apnay 167 k baad 172 likhna tha phir nxt 177 likhna tha lakin app nay dono 177 he likh dia hay

2 b)

median=X childa =l+h/f(n/2-C.F)

is ma

l= the lower class boundary of the medain class(n/2)

h=the class intrval size of the median class

f = the class frequncy of tmedian class

n=sigma f=total frequncy

C.F=the cumulative frequenchy preceding the medin class cumulativ freq

c.b              f                     c.f

145-150        4                 4

150-155        6                  10

155-160       28                 38

160-165      58                    96

165-170     64                  160

170-175    30                  190

toal           190

median class or the modal class = (n/2)th=190/2=95 th (to see in c.f)

so the medain r modal class is 160-165         58                    96

by putng the valus in formula

medain = 160 +5/58(95-38)

=160+5/58(57)

=164.9138

sir median ka ans correct btaye plz

STA301 1st Assignment idea Solution Date:07-11-12

secnd qstion k a part ma ap ko medin ka formula dekan ha

median=X childa =l+h/f(n/2-C.F)

is ma

l= the lower class boundary of the medain class(n/2)

h=the class intrval size of the median class

f = the class frequncy of tmedian class

n=sigma f=total frequncy

C.F=the cumulative frequenchy preceding the medin class cumulativ freq

c.b f c.f
145-150 4 4
150-155 6 10
155-160 28 38
160-165 58 96
165-170 64 160
170-175 30 190
toal 190

median class or the modal class = (n/2)th=190/2=95 th (to see in c.f)
so the medain r modal class is 160-165 58 96
by putng the valus in formula
medain = 160 +5/58(95-3
=160+5/58(57)
=164.9138

q1 part A is is ok ?? help
classes Frequency Relative Frequency Cumulative Relative Frequency
148 - 155 11 0.244 0.244
155 - 162 19 0.422 0.666
162 - 169 10 0.222 0.888
169 - 176 4 0.089 0.977
176 - 183 1 0.022 0.999
is this ok???

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