sta301 1st assignment solution by ash

[ash]

if u find any mistake so plzzzzz tell

[+ M.Tariq Malik]

One more Solution

STA301_Assignment#01_Solution_(www.vustudents.ning.com)

[+ M.Tariq Malik]

One more idea 

STA301_Solved_Assignment#01

[+ 'DoLL Fãrî' Ҿ]

plz measurement waly ka ans bta dain plz plz plz plz

[shabbir ghuman]

Jazak Allah

Ash Dear ummmah

[2wn3cpyldgot0]

Class Number	class limit	Frequency	Relative Frequency (r.f)	Commulative frequency (c.f)	Relative comulative frequency r.f * c.f=r.cf
1	148 ­­- 152	6	6/45 = 0.133	6	0.789
2	153 - 157	11	11/45 = 0.244	17	4.148
3	158 - 162	14	14/45 = 0.311	31	9.641
4	163 - 167	9	9/45 = 0.2	40	8
5	168 - 172	3	3/45 = 0.066	43	2.838
6	173 - 177	2	2/45 = 0.044	45	1.98
		Total = 45

[+ 'DoLL Fãrî' Ҿ]

y relative cumulative frequency kasy ai?

[Usman Perwaiz]

yar ap ne relative cumulative frequency galat nikali hai.   is k lie formula ye hai:  c.f/total frequency.

yaha total frequency 45 hai. for example: first relative frequency:6/45=0.133   second:17/45=0.377  third:31/45=0.688 and so on.

[+ M.Tariq Malik]

Question 1:

a)   Following are the heights (in centimeters) of 45 female high school students. Prepare a frequency distribution of the data where the class width is 5, the number of classes is 6 and the smallest observation is 148. Also obtain the relative frequency and relative cumulative frequency.

170, 151, 154, 160, 158, 154, 171, 156, 160, 157, 160, 157, 148, 165, 158, 159, 155, 151, 152, 161, 156, 164, 156, 163, 174, 153, 170, 149, 166, 154, 166, 160, 160, 161, 154, 163, 164, 160, 148, 162, 167, 165, 158, 158, 176.

 

Ans:

                  Smallest value(X0) = 148

                  Largest value (xm) = 176

                  Range = Xm – X0 = 176 – 148 = 28

                  Class interval = h = Range/ No of classes

                                             = 28 / 6 = 4.6 ~ 5

                 

Class Number	class limit	Frequency	Relative Frequency	Relative cumulative frequency
1	148 ­­-152	6	6/45 = 0.133	0.133
2	153 – 157	11	11/45 = 0.244	0.133+0.244 = 0.377
3	158 – 162	14	14/45 = 0.311	0.377+0.311=0.688
4	163 – 167	9	9/45 = 0.2	0.688+0.2=0.888
5	168 – 172	3	3/45 = 0.066	0.888+0.066=0.954
6	173 - 177	2	2/45 = 0.044	0.954+0.044=0.998
		Total = 45

 

b)     Which level of measurement (scale of measurement) is suitable for the following data in each example?

 

i) The lake Saif-ul-Muluk is 10,578 feet above from the sea level. 

ii) If customers go to the shop for buying shoes and try different size of shoes. The sizes of shoes are 7B, 10D and 12E.

iii) The numbering on T-shirts of players in the cricket team.

iv) The weight of the person is 68 kg.

Question 2:

 

a)      Find the median, harmonic mean and 23^rd percentile for the following frequency distribution.

 

Class Boundaries	Frequency	CF	X	1/x	F(1/x)
145 – 150	4	4	147.5	0.0067	0.0268
150 – 155	6	10	152.5	0.0065	0.039
155 – 160	28	38	157.5	0.0063	0.1764
160 – 165	58	96	162.5	0.0061	0.3538
165 – 170	64	160	167.5	0.0059	0.3776
170 – 175	30	190	172.5	0.0057	0.171

 

Median:

 

 

                                                         

                                                         Plz calculate it             

Harmonic mean:

 

 

23^rd Percentile:

                                                          

 

 

b)     Explain the concept of Geometric mean? Also find the geometric mean for the following data.

 

18, 19, 19, 19, 19, 20, 20, 20, 20, 20, 21, 21, 21, 21, 22, 23, 24, 27, 30, 36   

 

 

Ans:

 

Geometric mean G of a set of n positive values X1, X2…Xn is defined as the positive nth root of their product.

 

 

                                      

 

 

 

 

X	logX
18	1.2552
19	1.2787
19	1.2787
19	12.787
19	1.2787
20	1.3010
20	1.3010
20	1.3010
20	1.3010
20	1.3010
21	1.3222
21	1.3222
21	1.3222
21	1.3222
22	1.3424
23	1.3617
24	1.3802
27	1.4313
30	1.4771
36	1.5563
	∑logX =

 

 

 

   

 

 

G = antilog 1.33564 = 21.65

[Adnan]

U can also calculat ur result from this calculator on side

http://www.sengpielaudio.com/calculator-geommean.htm

[Adnan]

U can also calculate Ur ANTILOG from online calculator on the side

http://ncalculators.com/number-conversion/anti-log-logarithm-calcul...

[+ M.Tariq Malik]

[khurram shahzad]

please pay attention the formula of harmonic mean is not correct because it is used in ungrouped data as we know that in the question we have provided group data so please resolve your question with correct mean to say with grouped formula