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# sta301 1st assignment solution by ash

if u find any mistake so plzzzzz tell

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I think there is some problem in you Median.............. I have calculated like that

any one please give the solution of question one part (b)

please check your solution again because i think it is going to be wrong, the reason in mistake in your calciulation, the correct answer is 163.621

Khurram bhai ap ka answer 163.621 wrong ha... Asim ka solution teek ha

U can also calculate ur Geometric Mean result from calculator on this side

http://www.sengpielaudio.com/calculator-geommean.htm

q2 ma H.M k liye f/x find krna hai answer 164.862 ata hai

in question number 2 the calculation of cumulative frequency mean to say C.F is 190 not 180. so please check your answer before to solve it

STA301_100%_Correct_Solution

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Fall2012_STA301_1_SOLUTION

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thanks tariq bhai

plz 2nd question ke part 1 ka median part show kr dy plz

Question 1:                                                                                                                   Marks: 5+2=7

a)   Following are the heights (in centimeters) of 45 female high school students. Prepare a frequency distribution of the data where the class width is 5, the number of classes is 6 and the smallest observation is 148. Also obtain the relative frequency and relative cumulative frequency.

170, 151, 154, 160, 158, 154, 171, 156, 160, 157, 160, 157, 148, 165, 158, 159, 155, 151, 152, 161, 156, 164, 156, 163, 174, 153, 170, 149, 166, 154, 166, 160, 160, 161, 154, 163, 164, 160, 148, 162, 167, 165, 158, 158, 176.

 Classes (f) r.f r.c.f 148 - 152 6 6/45 = ans 0.133 153 - 157 11 11/45 =ans 0.377 158 - 162 14 14/45 = ans 0.688 163 - 167 9 9/45 = ans 0.888 168 - 172 3 3/45 =ans 0.955 173 - 177 2 2/45 = ans 0.999 45

b)     Which level of measurement (scale of measurement) is suitable for the following data in each example?

i)                    The lake Saif-ul-Muluk is 10,578 feet above from the sea level. (Ratio Scale)

ii)                  If customers go to the shop for buying shoes and try different size of shoes. The sizes of shoes are 7B, 10D and 12E. (Interval Scale)

iii)                The numbering on T-shirts of players in the cricket team.  (Ordinal Scale)

iv)                The weight of the person is 68 kg. (Nominal Scale)

Question 2:                                                                                                                   Marks: 5+3=8

a)      Find the median, harmonic mean and 23rd percentile for the following frequency distribution.

 Class Boundaries Frequency 145 – 150 4 150 – 155 6 155 – 160 28 160 – 165 58 165 – 170 64 170 – 175 30

Solution:

 Boundaries f c.f 145 – 150 4 4 150 – 155 6 10 155 – 160 28 38 160 – 165 58 96 165 – 170 64 160 170 – 175 30 190

median=l + h/f(n/2− c)

l = 164,h = 5,f = 64,n = 190,c = 96

 Class Boundaries Frequency X 1/X F(1/X) 145 – 150 4 (145 + 150)/2 0.007 0.03 150 – 155 6 - 0.007 0.04 155 – 160 28 - 0.006 0.2 160 – 165 58 - 0.006 0.4 165 – 170 64 - 0.006 0.4 170 – 175 30 - 0.006 0.2 190 TOTAL=

H.M =n/{∑f(1/x)}

 boundaries f c.f 145 – 150 4 4 150 – 155 6 10 155 – 160 28 38 160 – 165 58 96 165 – 170 64 160 170 – 175 30 190

P23 = l + h/f(23n/100 − c)

l=164,h = 5,f = 64,n = 190,c = 96

b)     Explain the concept of Geometric mean? Also find the geometric mean for the following data.

18, 19, 19, 19, 19, 20, 20, 20, 20, 20, 21, 21, 21, 21, 22, 23, 24, 27, 30, 36

Solution:

 x logx 18 1.26 19 1.27 19 1.27 19 1.27 19 1.27 20 1.30 20 1.30 20 1.30 20 1.30 20 1.30 21 1.32 21 1.32 21 1.32 21 1.32 22 1.34 23 1.36 24 1.38 27 1.43 30 1.48 36 1.56 19.46

g.m = log G = (∑ log X)/n

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