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two fair dice are rolled make sample space and what is the sum of outcome that 7. 5marks
why stadndard deviation is better than mean deviation. 2marks
values are given find moments ratio b1 and b2. 3marks
AunionB and AintersectionB find 2marks.
1 qo to calculate mean mode and median
today's paper of sta301........
very easy for me...about 10 question was of playing cards exAMLE....another example of pair die and tossed dice were also in mcqs.
all MCQs were repeated and came from this forum helpline..but 2 long questions were lil difficult.
overall paper was gud.
thanx for the past solved papers. it works.
Read more: Today's Paper  Virtual University of Pakistan http://vustudents.ning.com/group/sta301statisticsandprobability/for...
STA301 Current Midterm Paper May 2013
STA301 Current Midterm Paper May 2013
Total questions were 26.
MCQs were 20, from past paper and very easy.
Do learn all the concepts of Probability.
Subjective questions were 6.
Two of two marks, Two of 3marks and 2 of Five marks.
Complete the formula for Conditional probability P (A/B) = P( A intersection B) / ? (2marks)
what is "five number summary" (2marks)
P(A) = 0.60, P(B) = 0.40 P(A intersecrion B) = 0.24, Find P(AUB) = ? (3marks)
Find the skewness, mean and mode were given? (3marks)
Find the two moment mean of the following ungrouped data.(5marks)
Two dice are rolled write it's sample space and what is the probability that 5 will occur (5 marks)
Do pray for my next exam
===========
My today's STA301 paper:
Total marks: 40
Total qs: 26
Total mcqs: 20
The subjective questions were:
Which numbers are included in five number summary? (2 marks)
Find out the missing element: P(A/B)=P(A intersection B)/? (2 marks)
The values of Xo, Q2 (median) and Xm were given, we had to discuss the skewness of the distribution. (3 marks)
A committee of of four members is to be chosen from a total of ten persons. In how many ways this could be done? (the formula was also to be written). (3 marks)
Sets A, B and S were given, prove: AUB (complement)=A(complement) intersection B(complement), (Demorgan's law). (5 marks)
The values of X were given, had to calculate the coeffecient of skewness. (5 marks)
Hope it will help the students, who still have to attempt STA301 paper...
Thanks...
Regards...
============
odays STA301 solved paper 25 may 2013
For a positively skewed distribution m3 will be:
► Positive (Page 119)
► Negative
► Zero
► 1
Which one is the formula of range?
► xmxo
► 0 m x x
► 0 2 m x x
► (Page 80) 0 2 m x x
Which one of the following measurement does not divide a set of observations into equal parts?
► Quartiles
► Deciles
► Percentiles
► Standard deviations
The number of ways in which 4 books can be arranged
► 4
► 6
► 12
► 24
If X and Y are independent, then Var(XY) is equal to:
► Var(X)Var(Y)
► () () VarXVarY
► () VarX Y
► Zero
If any value in the data is zero, then it is not possible to have:
►Harmonic Mean
►Arithmetic Mean
►Median
►Mode (rep)
A coin is tossed 3 times then, the number of sample points in the sample space is:
►3
►8 (Page 145)
►6
►4
The approximate number of observations in a set of data covered by the interval, Median Q.D are:
►50 per cent (Page 84)
►68.5 per cent
►95.4 per cent
►99 per cent
In a set of 10 values all the values are 5, what is the value of 5th Decile:
►2
►5
►10
►20
A population that can be defined as the aggregate of all the conceivable ways in which a specified event can happen is known as:
►Infinite population
►Finite population
►Concrete population
►Hypothetical population (Page 12)
A histogram consists of a set of adjacent rectangles whose bases are marked off by:
►Class boundaries (Page 32)
►Class limits
►Class marks
►Class frequency
For positively skewed distribution
Mean…….Median…….Mode:
►=
►/p>
►> Click here for detail
►
How to find relative frequency distribution:
► Divide the class frequencies in half
► Divide the class frequency by the number of observations
► Find the difference between consecutive lower class limits
► Count the number of observations in the class
Which of the following is NOT a possible probability?
► 25/100
► 1
► 0
► 1
Data collected from Ministry of food is:
► Ungrouped data
► Secondary data
► Primary data
► Arrayed data
A frequency polygon is obtained by plotting the class frequencies against what?
Select correct option:
Class bounday
cumulative frequency
relative frequency
mid point
Subjective
Q.1 Find out the missing element P(AB) = ?/P(B) ( Marks: 2 )
P(AB) = P(A∩B) /P(B)
Q.2 What is meant by b in the linear regress line y= a + bx? ( Marks: 2 )
b represent slope of the line.
Q.3 A card is chosen from a deck of 52 cards. What is the probability if it is a
a) Diamond
b) Spade
c) Diamond or Spade ( Marks: 3 )
n(S) = 52
Diamond cards = n(A) = 13 and Spade = n(B) = 13
a) P(A) = n(A)/n(S) = 13/52
b) P(B) = n(B)/n(S) = 13/52
c) P(AUB) = P(A) + P(B)
= 13/52 + 13/52 = 26/52 = 1/2
Q.4 Consider the following values of moments:
= 0, = 20.5, = 35.2 and = 1204
Find the coefficient of skewness and kurtosis (). ( Marks: 3 )
Q.5 Compute the mean deviation from mean for the following data. (Where Mean X= 18.6 )
X 14.5 16.5 18.5 20.5 22.5
Frequency 3 5 11 7 3 ( Marks: 5 )
X
F
f
14.5
3
4.1
4.1
12.3
16.5
5
2.1
2.1
10.5
18.5
7
0.1
0.1
1.1
20.5
11
1.9
1.9
13.3
22.5
3
3.9
3.9
11.7
SUM
29
48.9
Q.6 A husband and wife appear in an interview for two vacancies in the same post. The probability of husband’s selection is 2/7 and probability of wife’s selection is 3/5. ( Marks: 5 )
What is the probability that only husband is selected?
==========
today's paper of sta301........
very easy for me...about 10 question was of playing cards exAMLE....another example of pair die and tossed dice were also in mcqs.
all MCQs were repeated and came from this forum helpline..but 2 long questions were lil difficult.
overall paper was gud.
thanx for the past solved papers. it works.
=============
Total: 26 Questions
20 MCQs
2 Short Questions Each of 2 marks.
Define disjoint sets.
Why a standard deviation is better than mean absolute deviation?
2 Short Questions each of 3 marks.
For a data mean=141, mode= 122.5 and . Calculate the Pearson’s Coefficient of skewness.
A ball is selected at random from a bag contains 2 white, 5 black, and 7 green balls. What is the probability that it is a:
i) White ball
ii) Green ball
2 Short Questions each of 5 marks.
Calculate the coefficient of standard deviation for the data given below:
X= 111, 123, 153, 173, 129
Three horses A, B and C are in a race; A is twice as likely to win as B and B is twice as likely to win as C. Assume that events are mutually exclusive. What is the probability that A or B wins?
Total questions were 26.
MCQs were 20, from past paper and very easy.
Do learn all the concepts of Probability.
Subjective questions were 6.
Two of two marks, Two of 3marks and 2 of Five marks.
Complete the formula for Conditional probability P (A/B) = P( A intersection B) / ? (2marks)
what is "five number summary" (2marks)
P(A) = 0.60, P(B) = 0.40 P(A intersecrion B) = 0.24, Find P(AUB) = ? (3marks)
Find the skewness, mean and mode were given? (3marks)
Find the two moment mean of the following ungrouped data.(5marks)
Two dice are rolled write it's sample space and what is the probability that 5 will occur (5 marks)
STA301 paper:
Total marks: 40
Total qs: 26
Total mcqs: 20
The subjective questions were:
STA301 solved paper 25 may 2013

Which one of the following measurement does not divide a set of observations into equal parts?
► Quartiles
► Deciles
► Percentiles
► Standard deviations

If X and Y are independent, then Var(XY) is equal to:
► Var(X)Var(Y)
► () () VarXVarY
► () VarX Y
► Zero

If any value in the data is zero, then it is not possible to have:
►Harmonic Mean
►Arithmetic Mean
►Median
►Mode (rep)

A coin is tossed 3 times then, the number of sample points in the sample space is:
►3
►8 (Page 145)
►6
►4

The approximate number of observations in a set of data covered by the interval, Median Q.D are:
►50 per cent (Page 84)
►68.5 per cent
►95.4 per cent
►99 per cent

In a set of 10 values all the values are 5, what is the value of 5th Decile:
►2
►5
►10
►20

A population that can be defined as the aggregate of all the conceivable ways in which a specified event can happen is known as:
►Infinite population
►Finite population
►Concrete population
►Hypothetical population (Page 12)

How to find relative frequency distribution:
► Divide the class frequencies in half
► Divide the class frequency by the number of observations
► Find the difference between consecutive lower class limits
► Count the number of observations in the class
Which of the following is NOT a possible probability?
► 25/100
► 1
► 0
► 1
Data collected from Ministry of food is:
► Ungrouped data
► Secondary data
► Primary data
► Arrayed data
A frequency polygon is obtained by plotting the class frequencies against what?
Select correct option:
Class bounday
cumulative frequency
relative frequency
mid point
Q.5 Compute the mean deviation from mean for the following data. (Where Mean X= 18.6 )
X 14.5 16.5 18.5 20.5 22.5
Frequency 3 5 11 7 3 ( Marks: 5 )

X

F

f


14.5

3

4.1

4.1

12.3

16.5

5

2.1

2.1

10.5

18.5

7

0.1

0.1

1.1

20.5

11

1.9

1.9

13.3

22.5

3

3.9

3.9

11.7

SUM

29

48.9

Q.6 A husband and wife appear in an interview for two vacancies in the same post. The probability of husband’s selection is 2/7 and probability of wife’s selection is 3/5. ( Marks: 5 )
What is the probability that only husband is selected?

paper main graph bi hai k nae banane k leye?????????
STA301  May – June 2013  MidTerm
Aaj ka paper STA301
SUBJECTIVE
21: Write a short note on fivenumber summary
22: Define the rule of permutation
23: For a data set, we have given the probability
P(A<= 1) = 0.72
P(B> 3) = 0.24
Find P(A>1)and P(B<=3)
24: If Σ d_{i}=14 and n=7, then calculate the mean deviation.
25: Fit the least square regression line of Y on X for the given data.
X 
Y 
X^{2} 
XY 
1 
1 
1 
1 
2 
1 
4 
2 
3 
2 
9 
6 
4 
2 
16 
8 
5 
3 
25 
15 
Σ=15 
9 
55 
32 
26: The sample space of two fair dice is given below. Find the number of sample points in each event, where event A shows the sum of the outcomes is equal to 5, event C shows the sum of the outcomes is equal to 6 and event C shows the sum of the outcomes is equal to 7.
S= {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
Ali thanks for sharing ur paper
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