STA301 GDB Fall 2020 Solution & Discussion
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STA301 GDB Solution Fall 2020 26-11-2020
Description skewed okay subsequently symmetrical distribution in the case of symmetrical distribution the empirical relation state that those symmetrical distributions mean when our distribution is not symmetric mean is greater than median and median is greater than mod sithara negative skewed the empirical relation is mean is less than median and median is less than more according to carl pearson in case of moderately skewed or moderately asymmetrical distribution the value of the mean median and mode have the following empirical relations in case of relation mean minus mode is equal to 3 into a negative
STA01 GDB - 1 Solution fall 2020 ll VU Learning STA101 GDB 1 Solution fall 2020 STA301 GDB - 1 Solution fall 2020 STA301 GDB 1 Solution 2020
STA-301
GDB No 1 Solution
2020 by Raise for Success
Requirement:
What can you say of the skewness in each of the following cases?
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 = 3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median
Mean > Median > Mode
35.4 > 34.3 > 32.1 Positive skewed distribution
Mode = 3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571 Negative skewed distribution
Mode = 3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean
-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution
STA-301
GDB No 1 Solution
2020 by Raise for Success
Requirement:
What can you say of the skewness in each of the following cases?
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 = 3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median
Mean > Median > Mode
35.4 > 34.3 > 32.1 Positive skewed distribution
Mode = 3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571 Negative skewed distribution
Mode = 3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean
-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution
STA-301
GDB No 1 Solution
Requirement:
What can you say of the in each of the following cases?
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 = 3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median
Mean > Median > Mode
35.4 > 34.3 > 32.1 Positive skewed distribution
Mode = 3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571 Negative skewed distribution
Mode = 3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean
-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution
STA-301
GDB No 1 Solution
Requirement:
What can you say of the in each of the following cases?
Answer:
Mode = 3Median - 2Mean
32.1 = 3Median – 2(35.4)
32.1 = 3Median – 70.8
32.1 + 70.8 = 3Median
102.9 = 3Median
102.9 / 3 = Median
34.3 = Median
Mean > Median > Mode
35.4 > 34.3 > 32.1 Positive skewed distribution
Mode = 3Median - 2Mean
Mode = 3(1459) – 2(1403)
Mode = 4377 – 2806
Mode = 1571
Mean < Median < Mode
1403 > 1459 > 1571 Negative skewed distribution
Mode = 3Median - 2Mean
50 = 3(50) – 2Mean
50 = 150 – 2Mean
50 - 150= - 2Mean
-100 = - 2Mean
100 / 2 = Mean
50 = Mean
Mean = Median = Mode
50 = 50 = 50 Normal distribution
STA301 Statistics and Probability GDB 1 Solution & Discussion Fall 2020
STA301 GDB Solution:
Q= What can you say of the Skewness in each of following cases?
1= Mode= 32.1 and Mean= 35.4
2= Median= 1459 and Mean= 1403
3= Median= 50 and Mode= 50
Answer:
They ask us find about Skewness: So there are two types of Skewed.
1= Positive Skewed: Mean<Median<Mode
2= Negative Skewed: Mode>Median>Mean
Solution.
1= Mode= 32.1 and Mean= 35.4 So we find Median= ?
Formula: Mode=3 Medain-2 Mean
32.1= 3(Median) -2(35.4)
32.1= 3(Median) -70.8
32.1+70.8= 3(Median)
102.9= 3(Median)
102.9/3 = Median
34.3= Median
So it is Positive Skewed : Mean<Median<Mode = 35.4<34.3<32.1
2= Median= 1459 and Mean= 1403 So we find Mode=?
Formula: Mode = 3Median -2Mean
Mode = 3Medain -2Mean
Mode= 3(1459) -2(1403)
Mode= 4377-2806
Mode= 1571
So this is Negative Skewed: Mode>Median>Mean = 1571>1459>1403
3= Median= 50 and Mode= 50 So we Find Mean=?
Fomula: Mode = 3Medain -2Mean
Mode = 3Medain -2Mean
50= 3(50) -2(Mean)
2(Mean)= 150-50
2(Mean)= 100
2(Mean)/2 = 100/2 = 50
So, Mean= 50
So This is Normal Distribution: Mean=Median=Mode: 50=50=50
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