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Replies to This Discussion

What will be the output of following code segment? for (int i = 2; i<10; i++){ if ( i == 5) continue; cout i "," ; }

  • 2,3,7,8,9

  • 2,3,4,6,7,8,9

  • 2,3,4

  • 4,6,7,8,9

correct answer would be 

  • 2,3,4,6,7,8,9

cause at 5, it will not print only.

why??? give reason plz

{ if ( i == 5) continue;

at 5, it will revert back to loop and will not print number "5"

but number "4" will be printed.

While loop becomes infinite in which scenario _______.

  • When the condition is always False

  • When the condition is always True

  • Condition contains logical operators

  • Condition contains arithmetic operators


true 

  • In loops the conditions are of ______ kind of expressions

  • Boolean expressions

  • Constant expressions

  • Primary expressions

  • Secondary expression


  • Boolean expressions

What will be the output of the following while loop? int counter = 0 ; while(counter < 15) cout counter “ ”; counter++;

  • 1 2 3 4

  • 1 2 3 4 5

  • Compile time error

  • Infinite loop

error q??

correct ...error hi ata h

  •           When we call a function, its control

  • transfers to its Prototype

  • transfers to its definition

  • returns to statement following function call

  • The compiler stops execution of whole program


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