CS314 Introduction to Cellular Networks Assignment No 01 Spring 2020 Solution & Discussion Due Date: 29052020
Assignment No. 01 Semester: Spring 2020 CS314: Introduction to Cellular Networks 
Total Marks: 20
Due Date: 29^{th} of May 2020 

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Objectives: The objective of this assignment is to increase the learning capabilities of the students about:
· Frequency Planning · Cell Pattern · Channels Distribution · Network Cells
Assignment
Question – 1 10 Marks Consider a certain Cellular network system in which we had used frequencybased division duplexing mechanism. The total assigned bandwidth of the system is 100 MHz, whereas the network uses 30 KHz channel for full duplex communication. In view of this, you are required to calculate the following:
1. The complete channel bandwidth. 2. The maximum no. of channels available. 3. The no. of required channel per cell in a cluster having i= 3 & j = 2.
Note: All calculation steps and formulas carry marks. So, you need to write every step involved with justifications wherever required.
Question – 2 10 Marks Suppose we had an area covered using 10 Cells. Assume that during a busy hour, the number of calls per hour (Q_{i}) for each 10 cells is given as : 2000, 1500, 1300, 1000, 1900, 400, 670, 1300, 1900 and 2100.
Let us assume that 60 percent of the car phones will be used during this period (η_{c} = 0.6) and that one call is made per car phone.
You are required to calculate the total no of calls made in stated hour. Also calculate the total number of customers in the system.
Note: All calculation steps and formulas carry marks. So, you need to write every step involved with justifications wherever required.

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CS314 Introduction to Cellular Networks Assignment 1 Solution & Discussion Spring 2020
Credit: SAHAR SALEEM (BC190407354)
Q NO 1:
Total bandwidth / 30 KHz = 3.3333
30*33 = 990 10 left
Formula (N=i^{2}+ij+j^{2})
N=++
= +3*2+
= 9+6+4
= 19
Q NO 2:
Total number of customers in the system = total number of calls × η_{c}
= 14070 × 0.6
= 8442
Hence the total number of calls made in the stated hour is 14070 and the total number of customers in the system is 8442.
You are required to calculate the total no of calls made in stated hour. Also calculate the total number of customers in the system.
Total number of calls made in stated hour = 2000 + 1500 + 1300 + 1000 + 1900 + 400 + 670 + 1300 + 1900 + 2100
= 14070
yeh to meri assignment he.. m n khud bnai thi yeh
Itni jaldi apnay reply dy diya, mujhe smaj nae a raha kin lafzon sy shukriya ada kru apka.
CS314_Assignment_No_01_Solution_Spring_2020
Download the file, Click on the below link
The complete channel bandwidth.
Bandwidth is a fixed quantity, so it cannot be changed. Hence, the channel capacity is directly proportional to the power of the signal, as SNR = (Power of signal) / (power of noise). so for example a signaltonoise ratio of 1000 is commonly expressed as: 10 * log10(1000) = 30 dB.
Capacity = bandwidth * log2(1 + SNR)
Output1 : C = 30000 * log2(1 + SNR) = 30000 * 11.62 = 348600 bps
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