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CS401 Assignment No 01 Spring 2019 Solution & Discussion Due Date: 16-05-2019

Q1. Calculate the Effective Address and Physical Address for the following set of values. (10)
Segment: 0xFFFF
Offset =0x0800
Base: 0x0111
Index=0x0001

Q2. Calculate the Segment Address for the given set of Physical and Effective addresses. (10)
Physical address = 0x119B, Effective address = 0x10AB
Physical address = 0xFF9B, Effective address = 0x10FF

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Cs401 1st Assignment Solution 100% Correct

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CS401 1st assignment solution.
Q1. Calculate the Effective Address and Physical Address for the following set of values. (10)
Segment: 0xFFFF
Offset =0x0800
Base: 0x0111
Index=0x0001
Solution:
Formula:
Effective Address= Base+off set + index
Physical Address = Segment + Effective Address
First we calculate Effective Address
Effective Address = Base + off set + index
Offset = 0x0800
Base: 0x0111
Index = 0x0001
Effective Address = 0x0111 + 0x0800 + 0x0001
0x0912 Answer
Physical Address = Segment + Effective Address
0xFFFF+0x0912
0x10911 Answer
Q2. Calculate the Segment Address for the given set of Physical and Effective addresses. (10)
a. Physical address = 0x119B, Effective address = 0x10AB
b. Physical address = 0xFF9B, Effective address = 0x10FF
Solution:
Formula:
a) Segment Address = Physical Address – Effective Address
Address = 0x119B -0x10AB = 0x0F0 Answer
b) Segment Address = Physical Address – Effective Address
=0xFF9B – 0x10FF = 0x10911 Answer

CS401 Assignment 1 Solution

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CS401 Assignment 1 Solution Spring 2019

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