Cs401 assignment #1 . Due date 14 nov 2016

[Anjum Nawaz]

Computer Architecture and Assembly Language Programming (CS401)
Assignment # 01

Total marks = 20

Deadline Date
14th of November, 2016

Please carefully read the following instructions before attempting assignment.

RULES FOR MARKING
It should be clear that your assignment would not get any credit if:
The assignment is submitted after the due date.
The submitted assignment does not open or file is corrupt.
Strict action will be taken if submitted solution is copied from any other student or from the internet.

You should consult the recommended books to clarify your concepts as handouts are not sufficient.

You are supposed to submit your assignment in .doc or docx format.
Any other formats like scan images, PDF, zip, rar, ppt and bmp etc will not be accepted.

Topic Covered:
Registers
Intel Architecture
Register Architecture
Data Declaration
Addressing Modes

NOTE

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If you people find any mistake or confusion in assignment (Question statement), please consult with your instructor before the deadline. After the deadline no queries will be entertained in this regard.

For any query, feel free to email at:
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Questions No 01 10 marks
Write a complete assembly language code for the following pseudo code:

Initialize a variable named NUM1 with 04 as a Hexadecimal Number
Initialize a variable named NUM2 with 08 as a Hexadecimal Number
Initialize a variable named NUM3 with 12 as a Hexadecimal Number
Initialize a variable named NUM4 with 00 as a Hexadecimal Number

Initialize AX with zero 0
Initialize BX with zero 0

Move NUM1 into AX
Move NUM2 into BX
Add BX into AX

Move NUM3 into BX
Add BX into AX

Store AX into NUM4

Questions No 02 10 marks
Suppose, we have the following register values:
AX
0150

BX
AB5D

CX
FF0A

DX
1234

DS
CC20

CS
EF10

ES
225F

SS
E25F

SI
1212

SP
CD0F

BP
95F8

DI
BDEF

You are required to calculate the physical address generated by each of the following instructions.

ADD [bx+Di], CX
MOV DX, [SP+1652H]

Note: Each provided instruction is independent.

[Syed Muhammad Faraz]

its wrong i think

[Hassan Raza Shah]

ans i main EA=1694c PA main 0110 kese?

[+ M.Tariq Malik]

Q 1: Write a complete assembly language code for the following pseudo code:
Initialize a variable named “NUM1” with “04 as a Hexadecimal Number”
Initialize a variable named “NUM2” with “08 as a Hexadecimal Number”
Initialize a variable named “NUM3” with “12 as a Hexadecimal Number”
Initialize a variable named “NUM4” with “00 as a Hexadecimal Number”
Initialize AX with zero “0”
Initialize BX with zero “0”
Move NUM1 into AX
Move NUM2 into BX
Add BX into AX
Move NUM3 into BX
Add BX into AX
Store AX into NUM4

Solution :
[org 0x0100]
mov bx, 0
mov ax ,[num1]
mov bx ,[num2]
add ax, bx
mov bx, [num3]
add ax, bx
mov [num4], ax
mov ax, 0x4c00
Int 0x21
num1: dw 4
num2: dw 8
num 3: dw 12
num 4: dw 00

Questions No 02 10 marks
Suppose, we have the following register values:

AX 0150
BX AB5D
CX FF0A
DX 1234
DS CC20
CS EF10
ES 225F
SS E25F
SI 1212
SP CD0F
BP 95F8
DI BDEF

You are required to calculate the physical address generated by each of the following instructions.

ADD [bx+Di], CX
MOV DX, [SP+1652H]

Note: Each provided instruction is independent.
Solution:
Answer i:
Effective Address EA= Base +Index +Offset
=0x AB5D +0x BDEF +0x0000
=0x 1694c
Physical Address = segment*0x10+Effective Address
= 0x000*0x10+0x0110
=0x120
ANSWER ii:
Effective Address EA = Base + Index + Offset
=0x AB5D + 0x000 +0x1652
=0xC1AF
Physical Address = segment * 0x10 + Effective Address
= 0x0000 * 0x10 + 0xc1AF
=0xC1BF

[Malik Rizwan Ali]

Please see page no. 26 for clear answer of question No. 1 only change is that value of 12 regarding hex is 18. 

For second question u can only addition of segment register and offset where bx, di, sp and 1652h all are offset and segment registers are ds, es, ss and ds are respectively... 

furthermore for addition we may be added 0 at the end of segment and at the start of offset.... 

[Abdul wahid abbasi]

thnks

[+ M.Tariq Malik]

CS401 Assignment#01 Solution

[Abdul wahid abbasi]

[Haseeb]

ans i main EA=1694c PA main 0110 kese?

[Imhum MCS]

exactly.. i think it is wrong.. should be 1704 

[Syeda Alveena Gilani (BS- IT)]

please koi chek kr k batao mera ye solution theak ha kai dono questions k answers theak ha ya ni.

[Shahid Javid]

Org k baad
Mov ax, 0

[Muhammad Nawaz]

Can we add SP and 1652H???? I think offset is of 20bit it can't be added.

help anyone.