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# CS402 assignent 01 solution attached here

Assignment No. 01
SEMESTER Spring 2017
CS402- Theory of Automata

Total Marks: 20

Due Date: 03/05/2017

Instructions

It should be clear that your assignment will not get any credit  if:

• The assignment is submitted after due date.
• The submitted assignment does not open or file corrupt.
• The assignment is full or partially copied from (other student or ditto copy from handouts or internet).
• Student ID is not mentioned in the assignment File or name of file is other than student ID.
• The assignment is not submitted in .doc or .docx format.

`Your submission must include:`

• Assignment should be in .doc or .docx format.

Assignment submission through email is NOT acceptable

## Objective

The objective of this assignment is

• To give knowledge and understanding of Regular Expression.
• To be able to understand and draw the Finite Automata (FA).

Note:

•  Font style: “Times New Roman”
•  Font color: “Black”
•  Font size: “12”
•  Font in Italic is not allowed at all.
•  No formatting or bullets are allowed to use.
• Your answer should be precise and to the point, avoid irrelevant detail.

Lectures Covered: This assignment covers Lecture # 01 - 08

Question No: 01 (Marks:  10)

Consider; Draw transition table from following transitions.

At state x reading zero, go to state y

At state x reading 1, go to state z

At state y reading 1, go to state z

At state y reading 0, stay at y

At state z reading (0,1) stay at z

Note: x, y, z are the states where x is initial state and z is final state.

Question No. 02 (Marks:  10)

Draw an FA for the following finite language defined over alphabet set {0, 1} accepting the given words.

{^, 01,10,010,101}

Note: Do not draw the null state.

=====================================Ended=======================================

For any query about the assignment, contact at CS402@vu.edu.pk

GOOD LUCK

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### Replies to This Discussion

In initial state (+-) means null string accepted here

(initial state "+-")---0----(non-final state "2")---1---(final state "4+")

we get 01 here 0,1 is transition as shown in diagram with arrow.

(initial state "+-")---1----(non-final state "3")---0---(final state "5+")

we get 10 here 1,0 is transition as show in diagram with arrow.

(initial state "+-")---0----(non-final state "2")---1---(final state "4+")---0---(final state "5+")

we get 010 here 0,1,0 is transition as shown in diagram with arrow

(initial state "+-")---1----(non-final state "3")---0---(final state "5+")---1---("4+")

now we get 101 here 1,0,1 is transition as shown in diagram with arrow

except these all string are not accepted

check this!!

Attachments:

Saroo Butt thanks for sharing

bhai ap ka question no. 2 mein mistake ha ap ne null string kahan accept karwai ha??????????????????

or bqi ki non accept transition kahan draw ki ha .????????????

Bhai ya to True solution submit kro ya chup rahoo yaaar

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