CS431 Assignment 01 Spring 2021 Solution / Discussion Due Date: 17052021
Question No.1 (5 Marks) A wave is transmitted from a sender to receiver. It has an amplitude of 6.8 cm, a time period of 0.01 seconds and the distance from a crest to the neighboring trough of 14.8 cm. By writing all necessary formulas and calculation steps, determine the frequency of this wave. Answer: As we know that v = d/t = 0.148m/0.01s = 14.8m/s now v = f ë so f = v/ë f = 14.8m/s 6.8m = 2.18 Hz Question No. 2 (5 Marks) Calculate the wavelength of a wave, having speed/velocity equal to 30,000 nm/s and frequency equal to 60 hertz. Answer: As we know that v = 30,000nm/s = 30,000*10^{9}m/s = 0.3*10^{4}m/s v = f ë ë = v/f ë = 0.3*10^{4}m/s 60Hz = 0.005*10^{4} = 5*10^{7}m
Note: Write all necessary formulas, calculation steps along with the appropriate unit with your answer.
Question No.3 (5 marks) Identify oneway and twoway communication examples from the following:




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CS431 Assignment 1 Solution Spring 2021  Wireless Communication  100% Correct Solution
Question No.1 (5 Marks)
A wave is transmitted from a sender to receiver. It has an amplitude of 6.8 cm, a time period of 0.01 seconds and the distance from a crest to the neighboring trough of 14.8 cm. By writing all necessary formulas and calculation steps, determine the frequency of this wave.
Answer: As we know that
v = d/t = 0.148m/0.01s = 14.8m/s
now
v = f ë
so f = v/ë
f = 14.8m/s
6.8m = 2.18 Hz
Question No. 2 (5 Marks)
Calculate the wavelength of a wave, having speed/velocity equal to 30,000 nm/s and frequency equal to 60 hertz.
Answer: As we know that
v = 30,000nm/s = 30,000*10^{9}m/s = 0.3*10^{4}m/s
v = f ë
ë = v/f
ë = 0.3*10^{4}m/s
60Hz = 0.005*10^{4} = 5*10^{7}m
Note: Write all necessary formulas, calculation steps along with the appropriate unit with your answer.
Question No.3 (5 marks)
Identify oneway and twoway communication examples from the following:
Example 
Oneway \ Twoway 
Radio 
Oneway 
Cell phones 
Twoway 
TV 
Oneway 
WiFi 
Twoway 
Walkie talkie 
Twoway 
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