We have been working very hard since 2009 to facilitate in learning Read More. We can't keep up without your support. Donate.

www.vustudents.ning.com

 www.bit.ly/vucodes + Link For Assignments, GDBs & Online Quizzes Solution www.bit.ly/papersvu + Link For Past Papers, Solved MCQs, Short Notes & More

# CS501 Assignment No 4 Solution & Discussion Due Date: 11-01-2012

Question No 1

Marks: 5

Consider a floppy drive having a transfer rate of 48 KB per second is attached to a 32 bit, 10MIPS CPU using an interrupt driven interface. The drive has 16-bit data bus.

Suppose that the interrupt overhead is 10 instructions. Calculate the fraction of CPU time required to service this drive when it is active.

 Question No 2 Marks: 5

A hard disk with 10 platters has 512 tracks per platter, 512 sectors per track and 512 bytes/sector. What is the total capacity of the disk?

Question No 3

Marks: 5

How many platters are required for an 80GB disk if there are 2048 bytes/sector, 2048 sectors per track and 2048 tracks per platter?

+ http://bit.ly/vucodes (Link for Assignments, GDBs & Online Quizzes Solution)

+ http://bit.ly/papersvu (Link for Past Papers, Solved MCQs, Short Notes & More)

Views: 1110

Attachments:

### Replies to This Discussion

assignment solution

Attachments:

check ur 3rd q solution is wrong 2048*2048*2048 is equal to 6GB

nahi sir g, wrong nahi hai, 2*2*2= 8

if we multiply 2048 four time than 8192 mean 8GB

am i right

100 % accurate solution ..

see pg # 312, 324, 325 respectively for Q 1, 2 and 3. u can solve all three questions very easily

Idea solution same of other you can find..from Hand out

Example 3

A hard disk with 5 platters has 1024 tracks per platter,512 sectors
per track and 512 bytes/sector. What is the total capacity of the
disk?
Solution
512 bytes x 512
sectors=0.2MB/track
0.2MB x 1024 tracks=0.2GB/platter
Therefore the hard disk has the total capacity of 5 x 0.2=1GB

But in the lecture, the total capacity of hard disk is stated by the Lecturer is

5 x 2 x 0.2 = 2GB

As platters has 2 sides. so 0.2 GB/platter is of 1 side only.

Questions 1

48 / 2 = 24K

*10 = 245760 instruction per second.

Question 2

512 bytes * 512 sector = 0.2 MB / track

0.2 MB * 512 tracks = 0.1 GB /platter

10 * 0.1 = 1 GB

Question 3

2048 * 2048 * 2048 = 8 GB

80 / 8 = 1

## Latest Activity

S ι у α ♡ updated their profile
3 hours ago
5 hours ago
5 hours ago
+ !! Ήලᵯᵯℹ Ⲥⱨ !! + posted discussions
5 hours ago
5 hours ago
6 hours ago
+ ⵑⵑ ӍᎥŞŞ ⲤһᵘʳһშᎥⵏ ⵑⵑ + updated their profile
6 hours ago
+ !! Ήලᵯᵯℹ Ⲥⱨ !! + liked Ammara Sabir's discussion !!!!!!Muhabbat!!!!!!
6 hours ago
6 hours ago
6 hours ago
6 hours ago
6 hours ago

1

2

3

4

5