CS501 Assignment No 4 Solution & Discussion Due Date: 11-01-2012

[Muhamamd Siddique]

Question No 1		Marks: 5
Consider a floppy drive having a transfer rate of 48 KB per second is attached to a 32 bit, 10MIPS CPU using an interrupt driven interface. The drive has 16-bit data bus.   Suppose that the interrupt overhead is 10 instructions. Calculate the fraction of CPU time required to service this drive when it is active.
Question No 2   Marks: 5
A hard disk with 10 platters has 512 tracks per platter, 512 sectors per track and 512 bytes/sector. What is the total capacity of the disk?
Question No 3		Marks: 5
How many platters are required for an 80GB disk if there are 2048 bytes/sector, 2048 sectors per track and 2048 tracks per platter?

[+ M.Tariq Malik]

Please Discuss here about this assignment.Thaks

[Umeed]

assignment solution

[jin]

check ur 3rd q solution is wrong 2048*2048*2048 is equal to 6GB

[iftikhar ahmad]

nahi sir g, wrong nahi hai, 2*2*2= 8

[Usman Ali AutoLube PHP]

if we multiply 2048 four time than 8192 mean 8GB 

am i right 

[Mian Usama]

100 % accurate solution ..

[saadali]

see pg # 312, 324, 325 respectively for Q 1, 2 and 3. u can solve all three questions very easily

[05cha530rul7d]

Thanks saadali....

[Sajid Khan]

thnx to saadali once again 

[+((who am I))+]

Idea solution same of other you can find..from Hand out 

Example 3

A hard disk with 5 platters has 1024 tracks per platter,512 sectors
per track and 512 bytes/sector. What is the total capacity of the
disk?
Solution
512 bytes x 512
sectors=0.2MB/track
0.2MB x 1024 tracks=0.2GB/platter
Therefore the hard disk has the total capacity of 5 x 0.2=1GB

[Khurram Javaid]

You are right Amjad

But in the lecture, the total capacity of hard disk is stated by the Lecturer is

5 x 2 x 0.2 = 2GB

As platters has 2 sides. so 0.2 GB/platter is of 1 side only.

[+ M.Tariq Malik]

Questions 1
Answer

48 / 2 = 24K

*10 = 245760 instruction per second.

 

Question 2

Answer

512 bytes * 512 sector = 0.2 MB / track

0.2 MB * 512 tracks = 0.1 GB /platter

10 * 0.1 = 1 GB

 

Question 3

Answer

2048 * 2048 * 2048 = 8 GB

80 / 8 = 1