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# CS501 Assignment No 02 Solution & Discussion * Due Date: 29th January 2019.*

Assignment No. 2 has been uploaded on LMS and its due date is January 29, 2019.

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KOI TO SEND KR DY SOLUTION

solution plzzz

Quiz -1 :

Solution:

Accepting the gadget supports two bytes to store both in a solitary 16-bit activity, that is 9800/2 = 4800 cycles/sec of DMA required, or about 208.3 us between stolen cycles. The cycle length is 0.5 us (one clock), so the percent of misfortune is 100% * (0.5/208.3) ~~ 0.24%.

Hi,208.3 it comes from where ?

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# cs501 assignment 2 solution By Shazia

Attachments:

Div by Zero = Internal
Trap = Internal
Stack Overflow = Internal
Invalid Opcode = Internal
Arithmetic Overflow = Internal

Mouse Interrupt = External (Hardware)

Breakpoint = External (Software)
Mode Switch = External (Software)
File Deletion = External (Software)

First question ka tukka hi mara he... :( Difficult question

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