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CS508 Assignment 01 Fall 2020 Solution / Discussion

Problem Statement:

Problem Statement:The following code snippet contains some conditional (nested if else based) statements. Which are difficult to understand as they do not contain any starting or ending keywords against each statement. You, being a programing language expert, are required to put "then" and "end if/else" at appropriate places to get the desired result.
Code Snippet:At start, x contains 100 (i.e. x = 100)        if (x > 50)          x = x * 5          if (x > 500)          x = x - 350          if (x > 350)          x = x - 150          else          x = x + 150          else          x = x - 100          if (x > 500)          x = x - 150          if (x < 500)           x = x + 150          if (x == 500)           x = x + 200          else          x = x + 100          if (x > 650)          x = x - 100          else if (x < 650)          x = x + 100          else          x = x * 5          else          x = x + 50
At end, x contains 3250.Note: This is a language-free code, which does not require any specific programming language to compile or execute. You are simply required to guess the flow of execution on the basis of value of x and put "then" and "end if/else" at appropriate places (see the hint given below). Furthermore, you can also add extra lines or spaces in your solution as well.
Hint:
 Difficult to Understand Easily Understandable    if (a > b)b = 5elsea = 5 if (a > b) thenb = 5end ifelse thena = 5end else  


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Replies to This Discussion

          if (x > 500)

          x = x - 150

          if (x < 500)

          x = x + 150

          if (x == 500)

          x = x + 200

          else

          x = x + 100

          if (x > 650)

          x = x - 100

          else if (x < 650)

          x = x + 100

          else

          x = x * 5

          else

          x = x + 50

 

At end, x contains 3250.

Note:

This is a language-free code, which does not require any specific programming language to compile or execute. You are simply required to guess the flow of execution on the basis of value of x and put "then" and "end if/else" at appropriate places (see the hint given below). Furthermore, you can also add extra lines or spaces in your solution as well.

 

Hint:

 

Difficult to Understand

Easily Understandable

if (a > b)

b = 5

else

a = 5

if (a > b) then

b = 5

end if

else then

a = 5

end else

 

 

 

 

Good Luck

CS508 Assignment No. 1 Fall 2020 Solution by VU ACADEMY

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#CS5008 Assg No 1 :

Simple way of solution Assignment no.1 cs 508

Cs 508 Assignment full solution simple

CS508 Assignment 1 Fall 2020 Solution
#vu #cs508 #AssignmentHelp #assignment #vustudent

link below 

CS508.cpp

#CS508 Assignment 1 IDEA SOL Fall 2020
if (x > 50)
then
x = x * 5;
if (x > 500)
then
x = x - 350;
if (x > 350)
then
x = x - 150;
end if
else
then
x = x + 150;
end else
end if
else
then
x = x - 100;
if (x > 500)
then
x = x - 150;
end if
if (x < 500)
then
x = x + 150;
if (x == 500)
then
x = x + 200;
end if
else
then
x = x + 100;
if (x > 650)
then
x = x - 100;
end if
else if (x < 650)
then
x = x + 100;
end if
else
then
x = x * 5;
end else
end else
end if
else
then
x = x + 50;
end else
end else
end if

CS508 Assignment#01 Solution click on the below link 

CS508_Assignment_1_IDEA_SOL_Fall_2020

CS508 Modern Programming Languages Assignment 1 Solution & Discussion Fall 2020


Solution Idea:

 

if (x > 50)

then

x = x * 5;

if (x > 500)

then

x = x - 350;

if (x > 350)

then

x = x - 150;

end if

else

then

x = x + 150;

end else

end if

else

then

x = x - 100;

if (x > 500)

then

x = x - 150;

end if

if (x < 500)

then

x = x + 150;

if (x == 500)

then

x = x + 200;

end if

else

then

x = x + 100;

if (x > 650)

then

x = x - 100;

end if

else if (x < 650)

then

x = x + 100;

end if

else

then

x = x * 5;

end else

end else

end if

else

then

x = x + 50;

end else

end else

end if

if (x > 50)
then
x = x * 5;
if (x > 500)
then
x = x - 350;
if (x > 350)
then
x = x - 150;
end if
else
then
x = x + 150;
end else
end if
else
then
x = x - 100;
if (x > 500)
then
x = x - 150;
end if
if (x < 500)
then
x = x + 150;
if (x == 500)
then
x = x + 200;
end if
else
then
x = x + 100;
if (x > 650)
then
x = x - 100;
end if
else if (x < 650)
then
x = x + 100;
end if
else
then
x = x * 5;
end else
end else
end if
else
then
x = x + 50;
end else
end else
end if

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