CS601 Assignment No 03 Solution & Discussion Due Date: 10-02-2015
Assignment No. 3
Semester: Fall 2014
Data Communication - CS601
Total Marks: 10
Due Date: 10/02/2015
To have the understanding of Transmission Impairments and Multiplexing.
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Six channels, each with a 75-kHz bandwidth, are to be multiplexed together. What is the minimum bandwidth of the link if there is a need for a guard band of 10 kHz between the channels to prevent interference? Give your answer in following table with correct values.
A signal travels through an amplifier and its power is increased 100 times. Calculate the amplification of the signal. Give your answer in following table with correct values and proper unit.
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See attached file - Slide No. 14
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Dear guys please tell me the correct formulas of both questions.
Guys tell me that this answer is right which i have solved.
For Six channels, we need at least five guard bands (Channels must be separated by strips of unused BW (guard bands) to prevent signals from Overlapping). This means that the required bandwidth is at least given as:
Total Channels = 6
Total Frequency of one channel = 75 KHz
Guard Band frequency b/w channels = 10 KHz
Bandwidth = Freq. of one channel × Total Channels + Guard band freq. × Total guard bands
Bandwidth = 75 × 6 + 5 × 10
Bandwidth = 450 + 50
Bandwidth = 500 KHz Ans.
Bandwidth with proper Unit
A signal travel through an amplifier and its power increases 100 times. This mean that P2 = 100P1
In this case, the amplification (gain of power) can be calculated as
10 log10 (P2/P1) = 10 log 10(100P1/P1)
=10 log10 (100)
= 10 (2)