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# CS601 Current Mid Term Papers Nov 2011, (Fall 2011)

Current Mid Term Papers Nov 2011, (Fall 2011)

Current Spring 2011 Papers, May 2011 Papers, Mid Term Spring 2011 Papers, Solved Papers, Solved Past Papers, Solved MCQs

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Please Share your Current Papers Questions/Pattern here to help each other. Thanks

What do you mean by DC component?
If a signal includes a component of zero frequency, that component is called DC
(Direct Current) component or constant component.
With no DC component, a signal has an average amplitude of zero. With a DC
component, a signal has nonzero average amplitude.

CS601+Mega+Solved+MCQs+File+Mid+term+Exam+Preparation

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Aoa
thanx for sharing this,God bless u.

salam

thanx for this ...

thnks

Today 26-11-2011 CS601 Mid term paper fall 2011

Attachments:

cs601 todays paper
Mcq's from the past papers..
except the one..
what is the bandwidth of telephone signals
3300
3000
3100
3200

Q-The freq is 5hz find the period. [2marks]
Q-what do u mean by zero frequency?how it affects the signal? [2 marks]
Q-which layer of the OSI controls the data rate and how it works? [3marks]
Q-Discuss the following interface standard (digram) jo mujhe nzr hi nhi ai  [3 marks]
Q-What are the possible ways through which a signal containing DC component can send to receiver over transmission medium? [5marks]
Q-
a) What is the function of a modulator? What is the function of a demodulator?
b) Explain the asymmetry of 56K modems
[5 marks]

Question No. 17: Give the names of any two devices that can be used for connecting among following situations:
1. LAN to LAN
2. LAN to WAN
3. MAN to WAN
Question No. 18: Phase Modulation is one of the methods used for :
1. Analog to Digital Conversion
2. Analog o Analog Conversion
3. Digital to Analog Conversion
Question No. 19: What will be the frequency of a signal completing 10 cycle in one second?
Question No. 20: If 64 bits are sent over transmission medium in one second, what will be the bit rate and bit interval?
Question No. 21: How does DTE and DCE works together for end to end communication?
Question No. 22: Using HDB3 scheme, encode the signal “1100001011”
Question No. 23: Give advantages and disadvantages of Asynchronous and Synchronous transmission. Compare the both strategies.

paper should be based on 100% mcqs!

CS601 CURRENT MIDTERM SUBJECTIVE PAPER

Q-The freq is 5hz find the period. [2marks]
Q-what do u mean by zero frequency?how it affects the signal? [2 marks]
Q-which layer of the OSI controls the data rate and how it works? [3marks]

Q-What are the possible ways through which a signal containing DC component can send to receiver over transmission medium? [5marks]
Q-
a) What is the function of a modulator? What is the function of a demodulator?
b) Explain the asymmetry of 56K modems
[5 marks]
Question No. 17: Give the names of any two devices that can be used for connecting among following situations:
1. LAN to LAN
2. LAN to WAN
3. MAN to WAN
Question No. 18: Phase Modulation is one of the methods used for :
1. Analog to Digital Conversion
2. Analog o Analog Conversion
3. Digital to Analog Conversion
Question No. 19: What will be the frequency of a signal completing 10 cycle in one second?
Question No. 20: If 64 bits are sent over transmission medium in one second, what will be the bit rate and bit interval?
Question No. 21: How does DTE and DCE works together for end to end communication?
Question No. 22: Using HDB3 scheme, encode the signal “1100001011”
Question No. 23: Give advantages and disadvantages of Asynchronous and Synchronous transmission. Compare the both strategies.

all the MCQ's were 4om the past papers bt Q's were a little bit logical some of the Q's which i remember r

1.a sine wave has a frequency of 5HZ .what is its period,

2.how signals are controlled by

frequecy
phase
amplitude

3. why we require plus code modulation of data when converting audio signal from analog-to-digital?

4.which function of the session layer provide communication in half and full duplix?

5.why do we group bits into longer groups to send from one device to another?

1

2

3

4

5

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