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CS601 Data Communication Assignment No 02 Fall 2020 Solution / Discussion

Question No. 1                                                                                                                                                                     

 

Diagram given below is representing the Differential Manchester encoding scheme. You are required to carefully analyze the diagram and then write the binary pattern represented by the diagram:

 

Hint: First bit is 0 and its voltage level is negative to positive.

 

Give your answer in the following table:

 

 

 

 

 

 

 

 

 

 

 

 

Question No. 2

 

Suppose a telecommunication company’s booster is emitting a signal of 0.45W, which is being passed through 10 devices. It has been observed that 7 of these devices are encountering noise of 3 microwatts whereas other 3 devices are encountering noise of 2 microwatts. Considering this information, you are required to calculate overall Signal to Noise Ratio (SNR) and SNRdB by writing all necessary formulas and calculation steps.

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CS601-Updated-Correct-Solution-assignment-02

CS601 Assignment 2 Solution idea Fall 2020

 

Question No. 1                                                                                                                                                                      

 

Diagram given below is representing the Differential Manchester encoding scheme. You are required to carefully analyze the diagram and then write the binary pattern represented by the diagram:

 

Hint: First bit is 0 and its voltage level is negative to positive.

 

Give your answer in the following table:

 

Solution:

 

0

1

0

0

1

1

1

0

0

 

 

Question No. 2

 

Suppose a telecommunication company’s booster is emitting a signal of 0.45W, which is being passed through 10 devices. It has been observed that 7 of these devices are encountering noise of 3 microwatts whereas other 3 devices are encountering noise of 2 microwatts. Considering this information, you are required to calculate overall Signal to Noise Ratio (SNR) and SNRdB by writing all necessary formulas and calculation steps.

 

 

 

Solution:

                   Signal Power = 0.45W

            Noise Power of Devices = 7*0.0003

                                                    = 0.000021W

           Noise Power of Devices = 3*0.000002

                                                   = 0.000006W

           Total Noise Power = 0.000021 + 0.00006

                                          = 0.000027

            SNR – Signal to Noise Ratio = S/W

                                                           = 0.45/0.000027

                                                           = 16,666.66

            SNRdB                                  = 10(logSNR)

                                                          = 10(log16,666.66)

                                                          = 10(4.22)

                                                          = 42.21

 

 

 

 

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