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CS602 Assignment # 2 Solution & Discussion Fall 2011 last date is 11-11-2011

Question 20 marks
We have two vectors V1 = (1, 2, 3) and V2 = (4, 5, 6). 
Using these vectors evaluate the following. 
1. V1norm =? 6 marks
2. V1 + V2 =? 2 mark
3. V1.V2 =? 4 marks
4. V1 X V2 =? 8 marks

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Replies to This Discussion

Please Discuss...

today is last date anyone solved it or any ideas....

 

ANy ideas or solution cz today last date.

check out the page no 109 and 110 of hand outs in pdf version

aoa...also check pg#111 for the last question...regards

 

thnx

 

This is idea solution so do your own....

 

Question                                      20 marks

We have two vectors V1 = (1, 2, 3) and V2 = (4, 5, 6).

Using these vectors evaluate the following.

V1norm =?                                  6 marks

Solution:

V1 = <1, 2,3>

||v1|| = sqrt[(1* 1) + (2 * 2) + (3* 3)] = sqrt (1 + 4 + 9) = 3.74 approx

A unit vector is a vector with a length of 1. Normalizing a vector converts a vector to a unit vector. To normalize a

vector, divide each component by its length. Let’s normalize the vector from the previous example.

u = < 1/3.74, 2/3.74, 3/3.74> = <.267, .534, .802>

V1 + V2 =?                                 2 mark

Solution:

v1 + v2 = <1 + 4, 2 + 5, 3 + 6> = <5, 7, 9>

V1.V2 =?                                    4 marks

Solution:

v1 . v2 = (1 * 4) + (2 * 5) + (3 * 6)

             =(4+10+18)

             =32

V1 X V2 =?                                  8 marks

Solution:

v1 = <1, 2, 3>  v2 = <4, 5, 6>

x3 = (2 * 6) – (3 * 5) = 18 – 15 = 3

y3 = (3 * 4) – (1 * 6) = 12 – 6 =6

z3 = (1 * 5) – (2* 4) = 5 – 8 = -3

v1 X v2 = <3, 6, -3>

 

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