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# Assignment No. 03 Semester: Fall 2014 CS604 –Operating System Total Marks: 15 Due Date: 16/2/2015

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Assignment

Question 1:   (5 Marks)

Consider the following snapshot of a system:

 Allocation Max Available A B C D A B C D A B C D P0 1 1 1 2 3 4 2 2 1 2 3 4 P1 1 0 2 2 1 3 4 14 P2 1 4 5 6 2 7 5 8 P3 2 5 4 2 3 5 7 9 P4 1 5 2 7 1 6 3 9

 Need A B C D

Answer the following questions using the banker’s algorithm:

(a)   What is the content of the matrix Need?                                             5

(b)   Is the system in a safe state? If yes identify the safe sequence. Show the step by step execution by updating the data structure if necessary.                                                            10

NOTE:Do not put any query on MDB about this assignment, if you have any query then emailatcs604@vu.edu.pk.

Deadline: Your assignment must be uploaded/submitted on or before

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### Replies to This Discussion

@ Efficient...

Why can't we use P1 after <P4, P0> .... As need of P1 is 0   3   2   12 and available resources at that point are 3    8    6    13 .... i am confused at this point. Why did u use P2 at this point rather than P1....??

can u please explain this for me...?? thanx

<P4, P0, P1, P2, P3> is this wrong sequence..???

Ghalt hai apka table safe sequence thek hai bus

All processes screen short if i am wrong kindly correct me

Attachments:

mistake in available table.

see it again.

ZAki bhai plz send solution file

Mistake kya hy bro....

Bhai sahib ap ka P3 and P4 wala table thek nai hai sequence thek liya hua hai values nai thek

<p4,p3,p0,p1,p2> This is valid safe sequence?

Dear broo..

app ne to  p1 ki aginst.. koi values nhi ki..

in availble table ma..

Thanx bro...... I correct it

My safe sequence is <P4, P0, P1, P2, P3>

Last Row(P4) is:

Allocation: 1, 5, 2, 7

Need: 0, 1, 1, 2

Available: 5, 12, 13, 21

ANY one plz send solution file

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