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# CS604 –Operating System Dear Students, Assignment No.3 has been uploaded on LMS interface. Due date is 21-01-2016. Wish you best of luck!

Assignment No. 03
Semester: Fall 2015

CS604 –Operating System

Total Marks: 20

Due date:21-01-2016

Assignment Objective:

• Implementation of Banker’s algorithm
• To know algorithm working to check the safe and unsafe state
• Allocation, available and maximum utilization of resources checking
• Finding the safe sequence of process execution

• Your assignment must be in .doc format (Any other formats like scan images, PDF, bmp, etc will not be accepted).
• No assignment will be accepted through email.

Rules for Marking:

It should be clear that your assignment will not get any credit if:

• The assignment is submitted after due date.
• The submitted assignment does not open or file is corrupted.
• Your assignment is copied from internet, handouts or from any other student

(Strict disciplinary action will be taken in this case).

Assignment

Question

You have to show the working of Banker’s algorithm in this assignment. Consider four processes P0, P1, P2, P3 and three resource types A, B, C. Resource types A has 9 instances, Resource type B has 6 instances and resource type C has 4 instances. Maximum and allocated resources are given according to the following table.

 Process Allocation Max Available A B C A B C A B C P0 1 1 1 8 4 2 P1 3 2 0 4 3 1 P2 2 0 0 5 0 2 P3 2 1 1 7 4 3

You have to give the following:

• Give available resources in the table
• Show execution of the Banker’s algorithm by giving the table step wise
• Finally find the safe sequence of execution of processes

NOTE: Do not put any query on MDB about this assignment, if you have any query then email at cs604@vu.edu.pk.

No need to write theory. Just give tables.

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Attachments:

### Replies to This Discussion

koi too assignment solution file upload kara

plzzzz check is it correct???

Attachments:

By Kanza

work=122
finih....
p1=finish[1]=T, work=442
p2=finish[2]=T, WORK= 642
P3=FINISH[3]=T,work=853
p0=finish[0]=T,work=964

last one is , also find the safe sequence of execution of process
P1 P2 P3 p0
Available
A. B C
1. 2. 2
4. 4. 2
6. 4 2
8. 5 3

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