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CS609 System Programming Assignment No 4 Spring 2012

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plz anyone help for cs 609 solutionnnnnnnnnnnnnnnnnnnn

plz tell me any 1 is that correct or not,>>>>>>>>>>>>>

c=4, h=6, S=12, H'=16, S' = 63

=(4*16+6)*63+12-1

=(64+6)63+12-1

=4421

.............................

LBA to CHS>>>>>>>>>>

cylender =LBA/(heads per cylender*sectors per track)

LBA=4421, heads per cylender=16, sector per track is 63

So we have

4421/(16*63)

=4.386

.......please behno bhaio next solve e kr den agr kisi ko ata hay n ye b bta den k agr is me koi galti shlti hay to wo b sahi kr den.....:( :( :(

LBA theek hai bt yahan CHS k liye jo LBA value given hai wo use krni hai aur wo hai 4256

Cylinder = 4256/16*63 = 4

formula sb handouts pg#135 sy daikho values me btati hn

temp = 4256/16*63 = 224

sectors = 224/63+1

sectors = 36 total capacity jo bios function k according di v hai buk me  wohi hai 63*16*1024*512 = 504MB

nazma plz check it total data storage capacity.

cylinders x heads x sectors x sector size

1024 * 16 * 63 * 512 = 528482304 = 516 MB approx

yes, i agree with this statement that in book answer is 504MB, but if we calculate mannualy in excel and divided by 1024000, which is value of MB  than answer is 516MB.

Vivek who told you that I MB = 102400 Bytes?

I MB = 1024 * 1024 Bytes

Thanks Nazma

Please koi Part a k solution me b help kr day...........

li8 to aati nhe banda help kya karay

For Part a:

many factors affects the HDD storage capacity.
some of these are disks (platters), increase in surface area, density of megnetic media etc etc

ya thanks Osma it's right, sorry it's my mistake

guys according to handouts correct formulas ye hain:
temp = LBA % (heads per cylender*sectors per track)
sector = temp % sectors per track+1

where % means MOD.
change ur PC's calculator into scientific view, u can easily find MOD button in ur calculator.
thanx
so,
temp=4256%16*63
= 224
sec=224%63+1
= 36

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